Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 4)
4.
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
Answer: Option
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
 |
27x + 17y | = 23 |
| x+ y |
27x + 17y = 23x + 23y
4x = 6y
| |
x | = | 3 | . |
| y | 2 |
Discussion:
234 comments Page 19 of 24.
Dhiraj said:
1 decade ago
(la+lb)/(Sa+Sb)=23
la/sa=27
la/sb=17
sa/sb=?
sa/sb=3:2
la/sa=27
la/sb=17
sa/sb=?
sa/sb=3:2
Ankit said:
1 decade ago
Thanks Y.S.Rama Krishna
I understood the answer now. :)
I understood the answer now. :)
Naveen Kumar said:
1 decade ago
Hi I have one doubt.
How X and Y seconds become metres?
How X and Y seconds become metres?
Sangeetha said:
1 decade ago
This method is easiest method I can understand this sum.
Racha manish said:
1 decade ago
Let we have to assume those to get ratio of that speeds.
Anil said:
1 decade ago
If, 4x=6y.
Then how to come ratio 3:2?
How it possible?
Then how to come ratio 3:2?
How it possible?
Shrikant said:
9 years ago
@Narayan.
Your answer is good it is a bit easy method.
Your answer is good it is a bit easy method.
Ruthvik said:
6 years ago
Why we have to take x+y in denominator? Please explain.
Askar said:
1 decade ago
:) The simple formula use for this problem is S = v*t.
Het said:
1 decade ago
@Arashan has describe very well with formula of speed.
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