Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 4)
4.
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
Answer: Option
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
 |
27x + 17y | = 23 |
| x+ y |
27x + 17y = 23x + 23y
4x = 6y
| |
x | = | 3 | . |
| y | 2 |
Discussion:
233 comments Page 18 of 24.
Jay said:
5 years ago
I can't understand the answer clearly. please explain how we get 3 : 2?
Dileep kumar said:
1 decade ago
27x + 17y/(x+y) = 23;
27x + 17y = 23x + 23y;
4x = 5y;
x/y = 5/4.
27x + 17y = 23x + 23y;
4x = 5y;
x/y = 5/4.
Ishwarya said:
2 years ago
But why we can't use the formula of B:A?
Anyone, please explain me.
Anyone, please explain me.
(19)
James said:
1 decade ago
Can someone please explain to me how 27x+17y = 23x + 23y & 4x + 6y?
Taiwo said:
1 decade ago
I think I am contented with fathima explanation thank you all.
Tamil said:
1 decade ago
Hi friends.
How to use mod method to calculate this problem?
How to use mod method to calculate this problem?
Swaminathan said:
7 years ago
Hi,
According to me,
(27-23): (17-23),
4 : 6.
Am I right?
According to me,
(27-23): (17-23),
4 : 6.
Am I right?
Srinivasa raju said:
1 decade ago
Total Distance/Total Speed = Total Time;
27X+17Y/X+Y = 23.
27X+17Y/X+Y = 23.
Abhijith said:
10 years ago
One of the similar way to improve our aptitude knowledge.
Rohit said:
1 decade ago
Fast calculation = mod(23-17) : mod(23-27) = 6:4 = 3:2 .
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