Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 4)
4.
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
1 : 3
3 : 2
3 : 4
None of these
Answer: Option
Explanation:

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 27x metres,

and length of the second train = 17y metres.

27x + 17y = 23
x+ y

27x + 17y = 23x + 23y

4x = 6y

x = 3 .
y 2

Discussion:
237 comments Page 18 of 24.

Shree said:   7 years ago
Thanks for explaining the answer. It's easy to understand the solution now.

Adi said:   1 decade ago
Short cut:

T2 = 23-17 = 6.
T1 = 27-23 = 4.

S1/S2 = T2/T1.
= 6/4 = 3/2.

Jay said:   5 years ago
I can't understand the answer clearly. please explain how we get 3 : 2?

Dileep kumar said:   1 decade ago
27x + 17y/(x+y) = 23;

27x + 17y = 23x + 23y;

4x = 5y;

x/y = 5/4.

Ishwarya said:   3 years ago
But why we can't use the formula of B:A?

Anyone, please explain me.
(20)

James said:   1 decade ago
Can someone please explain to me how 27x+17y = 23x + 23y & 4x + 6y?

Taiwo said:   1 decade ago
I think I am contented with fathima explanation thank you all.

Tamil said:   1 decade ago
Hi friends.

How to use mod method to calculate this problem?

Swaminathan said:   7 years ago
Hi,

According to me,
(27-23): (17-23),
4 : 6.

Am I right?

Srinivasa raju said:   1 decade ago
Total Distance/Total Speed = Total Time;

27X+17Y/X+Y = 23.


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