Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 4)
4.
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
Answer: Option
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
 |
27x + 17y | = 23 |
| x+ y |
27x + 17y = 23x + 23y
4x = 6y
| |
x | = | 3 | . |
| y | 2 |
Discussion:
233 comments Page 17 of 24.
L.santhosh reddy said:
7 years ago
Here, they mentioned 23sec and17sec but in answer, they took it as 23m and 17m why?
Bhanu said:
1 decade ago
Take all x terms once side and why terms other side then subtract we get 4x = 6y.
Thavapriya A said:
5 months ago
How to solve the following step?
27x+17y =23x+23y.
Could anyone tell me please?
27x+17y =23x+23y.
Could anyone tell me please?
(17)
Azhagarsamy said:
1 decade ago
Simple @Anil.
4x = 6y.
Then x/y = 6/4.
x/y = 3/2.
Therefore the ratio is 3:2.
4x = 6y.
Then x/y = 6/4.
x/y = 3/2.
Therefore the ratio is 3:2.
Kiran said:
1 decade ago
X+Y is speeds of 2trains and 27x+17y is length of trains
so lenth/speed=time
so lenth/speed=time
Anil vattamwar said:
1 decade ago
Train1 time is = 27.
Train2 time is = 17.
Divide them = (27/17) => (3/2).
Train2 time is = 17.
Divide them = (27/17) => (3/2).
GrandMaster said:
1 decade ago
Very short form is:
(27-23):(23-17),
4:6,
2:3.
So the ratio is 2:3 or 3:2.
(27-23):(23-17),
4:6,
2:3.
So the ratio is 2:3 or 3:2.
Bijay said:
1 decade ago
Length = speed*time.
Means 27x+17y = (x+y)*23.
=>(27x+17x)/(x+y) = 23.
Means 27x+17y = (x+y)*23.
=>(27x+17x)/(x+y) = 23.
Shree said:
7 years ago
Thanks for explaining the answer. It's easy to understand the solution now.
Adi said:
1 decade ago
Short cut:
T2 = 23-17 = 6.
T1 = 27-23 = 4.
S1/S2 = T2/T1.
= 6/4 = 3/2.
T2 = 23-17 = 6.
T1 = 27-23 = 4.
S1/S2 = T2/T1.
= 6/4 = 3/2.
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