Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 4)
4.
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
1 : 3
3 : 2
3 : 4
None of these
Answer: Option
Explanation:

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 27x metres,

and length of the second train = 17y metres.

27x + 17y = 23
x+ y

27x + 17y = 23x + 23y

4x = 6y

x = 3 .
y 2

Discussion:
233 comments Page 16 of 24.

Dripta Majumdar said:   4 months ago
Why is the length of the platform not taken into consideration? Anyone, please explain to me.
(8)

Sharad said:   1 decade ago
@James.

27x+17y = 23x+23y.
27x-23x = 23y-17y.

4x = 6y.
4x/2 = 6y/2.

2x = 3y.
x/y = 3/2.

Mayank Yadav said:   8 years ago
(x+y) I am not understanding that where this comes here this question, please give answer.

Aditya said:   6 years ago
Distance is not relative why we add both the lengths?

We should only take either of them.

Kamanulla said:   6 years ago
A = 27 - 23sec = 4sec.
B = 23 - 17sec = 6sec.
A:B = 4:6 = 2:3 in Sec.
A:B = 3:2 in Speed.
(1)

Ajit said:   1 decade ago
Dear rohit,

Your calculation right but this furmula use in every cases or limited case?

Anil Bhadani said:   8 years ago
Its very shortcut and its very simple.

27-23 = 4
23-17 = 6
so,4:6 = 2:3 or 3:2 also.

Narayan said:   1 decade ago
27            17
23
23-17=6 27-23=4


Then ratio become 3:2

Nisha said:   1 decade ago
Hi friends .....

1 km =1000m
1 hr=3600s

So, km/hr = 1000/3600 = 5/18

It's clear.

Pobitro Ghosh said:   8 years ago
Relative time 1st train= 27-23=4,
second train= 23-17=6,
1st:2nd= 6:4=3:2,
Ans:3:2.


Post your comments here:

Your comments will be displayed after verification.