Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 4)
4.
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
Answer: Option
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
 |
27x + 17y | = 23 |
| x+ y |
27x + 17y = 23x + 23y
4x = 6y
| |
x | = | 3 | . |
| y | 2 |
Discussion:
237 comments Page 21 of 24.
Sudhan Vybow said:
8 years ago
Make it simple.
27-17 =6 :27-23 =4
6:4 or 3:2.
27-17 =6 :27-23 =4
6:4 or 3:2.
Rohan said:
5 years ago
Can the ratio be 2:3? Anyone explain me, please.
(3)
ARUN said:
1 month ago
I do not understand this. Please explain to me.
(3)
Niveditha said:
2 decades ago
Anyone please help me how this x+y is divided.
Sushma said:
2 decades ago
Thanks Ramakrishna, your answer is excellent.
Rekha Kondamangale said:
7 years ago
Formula is
The ratio of speed = ax+by /x+y.
The ratio of speed = ax+by /x+y.
BhargaV said:
1 decade ago
Why km/hr to m/sec conversion takes 5/18 ???
Janardhan said:
2 decades ago
It's correct method to solve this problem.
Lokesh said:
2 decades ago
27x - 24x = 23y - 17y
4x = 6y
x/y = 3/2.
4x = 6y
x/y = 3/2.
Meenu said:
5 years ago
@Poornima.
Thank you for the explanation.
Thank you for the explanation.
(2)
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