Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 4)
4.
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
Answer: Option
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
![]() |
27x + 17y | = 23 |
x+ y |
27x + 17y = 23x + 23y
4x = 6y
![]() |
x | = | 3 | . |
y | 2 |
Discussion:
233 comments Page 18 of 24.
Ankit said:
1 decade ago
Let Speed of Train A= x m/s
And Speed of Train B= y m/s
Time taken by Train A to cover distance equals to its length = 27 s
Time taken by Train B to cover distance equals to its length = 17 s
Total distance covered
---------------------- = Time taken to Cross each other
Total speed
(Length of train A)+ (Length of train B)
so, --------------------------------------- = 23 seconds
(Speed of train A) + (Speed of train B)
(Speed x time) of Train A + (Speed x time) of Train B
----------------------------------------------------- =23
(Speed of train A) + (Speed of train B)
27x + 17y
--------- = 23
x + y
27x + 17y = 23x + 23y
4x =6y
x/y= 3/2
And Speed of Train B= y m/s
Time taken by Train A to cover distance equals to its length = 27 s
Time taken by Train B to cover distance equals to its length = 17 s
Total distance covered
---------------------- = Time taken to Cross each other
Total speed
(Length of train A)+ (Length of train B)
so, --------------------------------------- = 23 seconds
(Speed of train A) + (Speed of train B)
(Speed x time) of Train A + (Speed x time) of Train B
----------------------------------------------------- =23
(Speed of train A) + (Speed of train B)
27x + 17y
--------- = 23
x + y
27x + 17y = 23x + 23y
4x =6y
x/y= 3/2
RAVI said:
1 decade ago
I can't get this step
(27x+17y) / (x+y) = 23
Why we have to use this? can any one explain me.
(27x+17y) / (x+y) = 23
Why we have to use this? can any one explain me.
Taiwo said:
1 decade ago
I think I am contented with fathima explanation thank you all.
FATHIMA said:
1 decade ago
The 1st train sec 27-23=4.
The 2nd train sec 23-17=6.
So both are divide by 2.
4/2=2, and 6/3=3.
So the ratio is 3:2 its right method?
The 2nd train sec 23-17=6.
So both are divide by 2.
4/2=2, and 6/3=3.
So the ratio is 3:2 its right method?
Ranjitha said:
1 decade ago
@ chanti
its length=speed*time
so length of first train=27*x mts
and length of 2nd train= 17*y mts
its length=speed*time
so length of first train=27*x mts
and length of 2nd train= 17*y mts
Shahul hameed.M said:
1 decade ago
Hi friends in smart way....
To find out the speed ratio so ,
formula is Length = speed*time
so,
speed = length /time
here 2 trains so two different length and speed so the formula
s1+s2=L1+L2/time
speed we don't know so we take X,Y for speed for 2 trains
respectively ....
use above formula:
X+Y=L1+L2/23
HERE
L1=speed*time (speed is not given so take it as X,time is given that is 27)
L2= speed*time (speed is not given so take it as Y,time is given that is 17)
SO L1=27X
L2=17Y
apply it,
X+Y=27X+17Y/23
SO SOLVE IT
23(X+Y)=27X+17Y
23X+23Y=27X+17Y
separate the X and Y terms so we get
23X-27X+23Y-17Y=0
WE GET:
-4X+6Y=0
6Y=4X
RATIO (means difference of X and Y)
SO FRIEND,
X/Y=6/4=3/2
SO THE RATIO IS 3:2
To find out the speed ratio so ,
formula is Length = speed*time
so,
speed = length /time
here 2 trains so two different length and speed so the formula
s1+s2=L1+L2/time
speed we don't know so we take X,Y for speed for 2 trains
respectively ....
use above formula:
X+Y=L1+L2/23
HERE
L1=speed*time (speed is not given so take it as X,time is given that is 27)
L2= speed*time (speed is not given so take it as Y,time is given that is 17)
SO L1=27X
L2=17Y
apply it,
X+Y=27X+17Y/23
SO SOLVE IT
23(X+Y)=27X+17Y
23X+23Y=27X+17Y
separate the X and Y terms so we get
23X-27X+23Y-17Y=0
WE GET:
-4X+6Y=0
6Y=4X
RATIO (means difference of X and Y)
SO FRIEND,
X/Y=6/4=3/2
SO THE RATIO IS 3:2
(1)
Ankit said:
1 decade ago
Thanks Y.S.Rama Krishna
I understood the answer now. :)
I understood the answer now. :)
Dheeraj said:
1 decade ago
Hi Lokesh,
Can you please explain why you've said 27x-24x=23y-17y.....?
I can't see figure of 24 ain't where???
Thanks in advance....
Can you please explain why you've said 27x-24x=23y-17y.....?
I can't see figure of 24 ain't where???
Thanks in advance....
Narayan said:
1 decade ago
27 17
23
23-17=6 27-23=4
Then ratio become 3:2
Mobarak said:
1 decade ago
If two trains running at the speed x & y respectively in opposit direction then their relative velocity is (x+y) m/s.
Now if two trains cross each other then they have to cross total length of two trains which is (27x+17y).
Now time taken for crssng the total length = (27x+17y)/(x+y) i.e 23.
Now if two trains cross each other then they have to cross total length of two trains which is (27x+17y).
Now time taken for crssng the total length = (27x+17y)/(x+y) i.e 23.
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