Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 4)
4.
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
1 : 3
3 : 2
3 : 4
None of these
Answer: Option
Explanation:

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 27x metres,

and length of the second train = 17y metres.

27x + 17y = 23
x+ y

27x + 17y = 23x + 23y

4x = 6y

x = 3 .
y 2

Discussion:
233 comments Page 18 of 24.

Ankit said:   1 decade ago
Let Speed of Train A= x m/s
And Speed of Train B= y m/s

Time taken by Train A to cover distance equals to its length = 27 s

Time taken by Train B to cover distance equals to its length = 17 s

Total distance covered
---------------------- = Time taken to Cross each other
Total speed


(Length of train A)+ (Length of train B)
so, --------------------------------------- = 23 seconds
(Speed of train A) + (Speed of train B)

(Speed x time) of Train A + (Speed x time) of Train B
----------------------------------------------------- =23
(Speed of train A) + (Speed of train B)

27x + 17y
--------- = 23
x + y

27x + 17y = 23x + 23y
4x =6y

x/y= 3/2

RAVI said:   1 decade ago
I can't get this step

(27x+17y) / (x+y) = 23

Why we have to use this? can any one explain me.

Taiwo said:   1 decade ago
I think I am contented with fathima explanation thank you all.

FATHIMA said:   1 decade ago
The 1st train sec 27-23=4.

The 2nd train sec 23-17=6.

So both are divide by 2.

4/2=2, and 6/3=3.

So the ratio is 3:2 its right method?

Ranjitha said:   1 decade ago
@ chanti
its length=speed*time
so length of first train=27*x mts
and length of 2nd train= 17*y mts

Shahul hameed.M said:   1 decade ago
Hi friends in smart way....

To find out the speed ratio so ,

formula is Length = speed*time
so,

speed = length /time

here 2 trains so two different length and speed so the formula

s1+s2=L1+L2/time

speed we don't know so we take X,Y for speed for 2 trains
respectively ....
use above formula:

X+Y=L1+L2/23

HERE
L1=speed*time (speed is not given so take it as X,time is given that is 27)

L2= speed*time (speed is not given so take it as Y,time is given that is 17)
SO L1=27X
L2=17Y
apply it,
X+Y=27X+17Y/23

SO SOLVE IT
23(X+Y)=27X+17Y
23X+23Y=27X+17Y

separate the X and Y terms so we get

23X-27X+23Y-17Y=0

WE GET:
-4X+6Y=0
6Y=4X

RATIO (means difference of X and Y)
SO FRIEND,

X/Y=6/4=3/2
SO THE RATIO IS 3:2
(1)

Ankit said:   1 decade ago
Thanks Y.S.Rama Krishna

I understood the answer now. :)

Dheeraj said:   1 decade ago
Hi Lokesh,

Can you please explain why you've said 27x-24x=23y-17y.....?


I can't see figure of 24 ain't where???

Thanks in advance....

Narayan said:   1 decade ago
27            17
23
23-17=6 27-23=4


Then ratio become 3:2

Mobarak said:   1 decade ago
If two trains running at the speed x & y respectively in opposit direction then their relative velocity is (x+y) m/s.

Now if two trains cross each other then they have to cross total length of two trains which is (27x+17y).

Now time taken for crssng the total length = (27x+17y)/(x+y) i.e 23.


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