Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 13)
13.
Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:
Answer: Option
Explanation:
Let the speed of the slower train be x m/sec.
Then, speed of the faster train = 2x m/sec.
Relative speed = (x + 2x) m/sec = 3x m/sec.
 |
(100 + 100) | = 3x |
| 8 |
24x = 200
| x = |
25 | . |
| 3 |
| So, speed of the faster train = | 50 | m/sec |
| 3 |
| = |  |
50 | x | 18 |  km/hr |
| 3 | 5 |
= 60 km/hr.
Discussion:
74 comments Page 8 of 8.
Manoj said:
1 decade ago
Please guide me step by step in calculation.
Nagashree said:
1 decade ago
In the question they have mentioned that we have to find the train which is twice as fast the other hence we have to multipy (25 x 2)/3 = 50/3.
Jagdish said:
2 decades ago
I don't understand how is speed of the faster train = 50/3 m/sec.
Ravi said:
2 decades ago
What is (100+100)/8=3x?
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