Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 13)
13.
Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:
Answer: Option
Explanation:
Let the speed of the slower train be x m/sec.
Then, speed of the faster train = 2x m/sec.
Relative speed = (x + 2x) m/sec = 3x m/sec.
 |
(100 + 100) | = 3x |
| 8 |
24x = 200
| x = |
25 | . |
| 3 |
| So, speed of the faster train = | 50 | m/sec |
| 3 |
| = |  |
50 | x | 18 |  km/hr |
| 3 | 5 |
= 60 km/hr.
Discussion:
74 comments Page 7 of 8.
Sonam said:
8 years ago
@Adityabala.
Nice explanation. Thanks.
Nice explanation. Thanks.
Arun said:
1 decade ago
What is 5/18? How the value will come?
Dinesh said:
1 decade ago
In this problem how we can take 50/3?
Sowdi said:
7 years ago
Thanks for your explanation @Sarang.
Harpreet singh said:
1 decade ago
Why multiply 50/3*18/5 in the last?
Nisha said:
4 years ago
How come 50/3? Please explain me.
(1)
Vijay arun said:
9 years ago
@Ikram.
Nice explanation.
Nice explanation.
Srinu said:
10 years ago
What is formula distance?
Nutan said:
7 years ago
(50/3) * (18/3) = 60 how?
Ravi said:
2 decades ago
What is (100+100)/8=3x?
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