Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 13)
13.
Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:
Answer: Option
Explanation:
Let the speed of the slower train be x m/sec.
Then, speed of the faster train = 2x m/sec.
Relative speed = (x + 2x) m/sec = 3x m/sec.
 |
(100 + 100) | = 3x |
| 8 |
24x = 200
| x = |
25 | . |
| 3 |
| So, speed of the faster train = | 50 | m/sec |
| 3 |
| = |  |
50 | x | 18 |  km/hr |
| 3 | 5 |
= 60 km/hr.
Discussion:
74 comments Page 6 of 8.
Jai said:
9 years ago
If 1st train accelerated by 0.3 and 2nd 0.2 then how to solve it?
Rajaprabu said:
1 decade ago
What is 18/5 and 5/18 ? why we are using please explain?
Charmi said:
1 decade ago
How did you reversed the 18/5 and multiplied with 50/3?
Studybeforexam said:
1 decade ago
25/3 + 25/3 = 50/3 i.e. 3 being a common denominator.
Kavitha said:
1 decade ago
I didn't understood how can I clear this problem?
Eudis said:
7 years ago
From where did 18/5 come? Please explain me.
Sam said:
9 years ago
@Aditiyabala.
Super explanation, Thank you.
Super explanation, Thank you.
Manoj said:
1 decade ago
Please guide me step by step in calculation.
Lavanya said:
1 decade ago
I don't understand please explain it brief.
Mounika said:
1 decade ago
What 50/3 I didn't understand this step?
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