Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
Speed of the train relative to man = | ![]() |
125 | ![]() |
10 |
= | ![]() |
25 | ![]() |
2 |
= | ![]() |
25 | x | 18 | ![]() |
2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
475 comments Page 43 of 48.
Nithish said:
7 years ago
Thanks all for the explanations.
Charanjeet pal said:
5 years ago
Why divide 18/5? Please explain.
Saji said:
2 decades ago
18/5 is to convert m/s to km/hr
(1)
G.Humayun said:
1 decade ago
Thanks friends its very useful.
Jaydev ramnath said:
9 years ago
Why it is 18/5? Please explain.
Tanvi said:
7 years ago
Why using 18/5? Please explain.
MAHA said:
1 year ago
How 18/5? Please explain to me.
(53)
Arjun said:
1 decade ago
Speed of man*time = 5*10 = 50.
Amit thakur said:
8 years ago
Thanks for these explanations.
Arup said:
8 years ago
What is 18/5?
Please explain.
Please explain.
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