Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
Speed of the train relative to man = | ![]() |
125 | ![]() |
10 |
= | ![]() |
25 | ![]() |
2 |
= | ![]() |
25 | x | 18 | ![]() |
2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
475 comments Page 42 of 48.
Vashu said:
1 decade ago
What is 5/18 and where its come in?
John said:
9 years ago
@Swati
To convert km/h into m/sec.
To convert km/h into m/sec.
ASHWINI said:
8 years ago
Thank to all the given explanation.
Apoorva Marathi said:
10 months ago
How it is 50? please explain to me.
(9)
Greeshma reddy said:
1 decade ago
How did this equation x-5=45 form?
ESWARAN.P said:
1 decade ago
Here using x-5=45. Please explain?
Yugapooja said:
6 years ago
Thanks for the explanation @Rahul.
Vikash gupta said:
7 years ago
Relative velocity is 125/10, how?
Prithika said:
1 decade ago
@kumar
cause speed=distance/time
cause speed=distance/time
Chandrasekar said:
8 years ago
Why using 18/5?
Please explain.
Please explain.
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