Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = | ![]() |
125 | m/sec |
| 10 |
| = | ![]() |
25 | m/sec. |
| 2 |
| = | ![]() |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
487 comments Page 42 of 49.
Krish said:
1 decade ago
How to be solve this 25/2*18/5 = 45?
Geeth said:
1 decade ago
Thank you all guys I got many ideas.
Pattinson said:
1 decade ago
18/5 is to convert seconds to hours.
Seshu said:
5 years ago
length = speed * time = 5 * 10 = 50.
(3)
Chetana said:
2 decades ago
Thanks frnd. I understand properly.
Jitendra Prajapati said:
1 decade ago
Very good explanation by Suganthan.
Vinod salunke said:
1 decade ago
Nice explanation by ramesh chandra.
Vashu said:
1 decade ago
What is 5/18 and where its come in?
John said:
10 years ago
@Swati
To convert km/h into m/sec.
To convert km/h into m/sec.
ASHWINI said:
9 years ago
Thank to all the given explanation.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers

m/sec