Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
45 km/hr
50 km/hr
54 km/hr
55 km/hr
Answer: Option
Explanation:

Speed of the train relative to man = 125 m/sec
10

   = 25 m/sec.
2

   = 25 x 18 km/hr
2 5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

x - 5 = 45         x = 50 km/hr.

Discussion:
475 comments Page 25 of 48.

GwenBiz said:   1 decade ago
@Jothi,

x-5 = 45.
We add 5 to both sides so that we stay with x.

x-5+5 = 45+5.
Therefore,

So x = 50.

Sai said:   1 decade ago
This concept is relative to distance not to time so you cannot take a relation like you have mentioned.

Stark said:   1 decade ago
Correct your equation to 125/v1-(10*5)/(5*18) = 10 you will get.

v1 = 13.88 m/s.
==> v1 = 50 kmph.

Sonali said:   6 years ago
If only one of the speed is given then how will we consider that which one is to be subtracted or not?

Kannips said:   1 decade ago
speed=distance/time.so speed=125/10.....25/2*18/5=45... the question is same direction=x-5=45 x=50

Anish said:   1 decade ago
Hi Manishkumar,Vijaykumarkuppani,Umesh
U hav cleard the points exactly how itz done.
Thanks a lot...

Dinesh kumar said:   5 years ago
The speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

Please explain it, friends.

Eric said:   1 decade ago
@Shafi.

This method is quite simple and explain the whole concept, thanks for the nice explanation.

Robi said:   7 years ago
@Omkar Tanpure.

What is the relative speed? And why 45 is called relative speed? Please explain me.

Muhammad Zulafqar said:   7 years ago
The simplest answer is;

10sec/1000Meter =0.01.
Then multiply with 5KM i.e 0.01 * 5000meter = 50KM.


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