Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = |  |
125 |  m/sec |
| 10 |
| = | |
25 | m/sec. |
| 2 |
| = | |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 
x = 50 km/hr.
Discussion:
493 comments Page 24 of 50.
Abid said:
1 decade ago
How to calculate what Km/Hr is train running if its length is 130 m and cross it own start point in 15 seconds?
Kumud Singh said:
8 years ago
@Ladura.
Distance covered by the man in 10 sec,
Speed = 5*5/18 = 25/18 m/sec,
Distance = 25/18*10 = 125/19 m.
Distance covered by the man in 10 sec,
Speed = 5*5/18 = 25/18 m/sec,
Distance = 25/18*10 = 125/19 m.
SURESHBABU KASTURI said:
1 decade ago
If two things are at same speed in same direction.
We subtract that,
So right 125-5=120.
Wrong is 125+5=130.
We subtract that,
So right 125-5=120.
Wrong is 125+5=130.
Naresh said:
6 years ago
Trian length/trainspeed - man speed = time.
So, 125/(x-5) * 5/18 = 10.
125 * 18/(x-5)5 = 10
X-5 = 45.
X = 50.
So, 125/(x-5) * 5/18 = 10.
125 * 18/(x-5)5 = 10
X-5 = 45.
X = 50.
Namith said:
5 years ago
What is the difference between the relative speed of train and the speed of the train? Anyone, please explain.
Farheen said:
8 years ago
To convert km/hr to m/sec we multiply it with 5/18.
If we are converting m/sec to km/hr we multiply it 18/5.
If we are converting m/sec to km/hr we multiply it 18/5.
Joy said:
10 months ago
Here;
1 km = 1000m.
1 hour = 3600 seconds,
Then you change the Km/hr to m/sec.
= 1000/3600.
= 5/18 m/second.
1 km = 1000m.
1 hour = 3600 seconds,
Then you change the Km/hr to m/sec.
= 1000/3600.
= 5/18 m/second.
(68)
Dhandapani said:
2 decades ago
Simple you can multiply 5*10.
5-a man running 5km/hr and the train reached in 10 seconds.
5*10=50km/hr.
5-a man running 5km/hr and the train reached in 10 seconds.
5*10=50km/hr.
Diksha said:
1 decade ago
How we come to know that the speed 5km\hr is the speed of the man because it is not given in the question?
Mani Sharma said:
1 decade ago
If train moving same direction = SUBTRACTION OCCUR.
If train moving opposite direction = ADDITION OCCUR.
If train moving opposite direction = ADDITION OCCUR.
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