Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = | ![]() |
125 | m/sec |
| 10 |
| = | ![]() |
25 | m/sec. |
| 2 |
| = | ![]() |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
494 comments Page 24 of 50.
Jasper said:
1 decade ago
How it is saying that relative speed of the train is 45?
Its only the speed of the train, can anyone tell me?
Its only the speed of the train, can anyone tell me?
Abid said:
1 decade ago
How to calculate what Km/Hr is train running if its length is 130 m and cross it own start point in 15 seconds?
Kumud Singh said:
8 years ago
@Ladura.
Distance covered by the man in 10 sec,
Speed = 5*5/18 = 25/18 m/sec,
Distance = 25/18*10 = 125/19 m.
Distance covered by the man in 10 sec,
Speed = 5*5/18 = 25/18 m/sec,
Distance = 25/18*10 = 125/19 m.
SURESHBABU KASTURI said:
1 decade ago
If two things are at same speed in same direction.
We subtract that,
So right 125-5=120.
Wrong is 125+5=130.
We subtract that,
So right 125-5=120.
Wrong is 125+5=130.
Naresh said:
6 years ago
Trian length/trainspeed - man speed = time.
So, 125/(x-5) * 5/18 = 10.
125 * 18/(x-5)5 = 10
X-5 = 45.
X = 50.
So, 125/(x-5) * 5/18 = 10.
125 * 18/(x-5)5 = 10
X-5 = 45.
X = 50.
Namith said:
5 years ago
What is the difference between the relative speed of train and the speed of the train? Anyone, please explain.
Farheen said:
8 years ago
To convert km/hr to m/sec we multiply it with 5/18.
If we are converting m/sec to km/hr we multiply it 18/5.
If we are converting m/sec to km/hr we multiply it 18/5.
Joy said:
11 months ago
Here;
1 km = 1000m.
1 hour = 3600 seconds,
Then you change the Km/hr to m/sec.
= 1000/3600.
= 5/18 m/second.
1 km = 1000m.
1 hour = 3600 seconds,
Then you change the Km/hr to m/sec.
= 1000/3600.
= 5/18 m/second.
(68)
Dhandapani said:
2 decades ago
Simple you can multiply 5*10.
5-a man running 5km/hr and the train reached in 10 seconds.
5*10=50km/hr.
5-a man running 5km/hr and the train reached in 10 seconds.
5*10=50km/hr.
Diksha said:
1 decade ago
How we come to know that the speed 5km\hr is the speed of the man because it is not given in the question?
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