Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = |  |
125 |  m/sec |
| 10 |
| = | |
25 | m/sec. |
| 2 |
| = | |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 
x = 50 km/hr.
Discussion:
478 comments Page 17 of 48.
Shro said:
1 decade ago
Thanku Rahul. Your explanation was easy to understand and cleared my doubts too :).
JRR said:
1 decade ago
Abhishek's answer explaines this clearly...Thanks Abhishek!!!
Ranjit R Pawar said:
1 decade ago
Thanks rahul.
Anish said:
1 decade ago
Hi Manishkumar,Vijaykumarkuppani,Umesh
U hav cleard the points exactly how itz done.
Thanks a lot...
U hav cleard the points exactly how itz done.
Thanks a lot...
Parvez khan said:
1 decade ago
How was the relative speed calculated ?
Ambikun said:
1 decade ago
There is no need of calculating relative speed. It can be solved easily by calculating the distance traveled by the man in 10 sec and the total distance covered by the train in the same time. This is very simple.
Sanghaniakshay said:
1 decade ago
Thanks abhishek.
Greeshma reddy said:
1 decade ago
How did this equation x-5=45 form?
PRADYUMNA KUMAR DAS said:
1 decade ago
If the man and train in opposite direction then it relative speed is x+5. And speed is x+5=45. =>x=40. Am I right?
Sada said:
1 decade ago
Any basic formula is there for this problem kindly explain.
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