Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 10)
10.
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
3.6 sec
18 sec
36 sec
72 sec
Answer: Option
Explanation:

Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.

   = 36 x 5 m/sec
18

   = 10 m/sec.

Distance to be covered = (240 + 120) m = 360 m.

Time taken = 360 sec = 36 sec.
10
Discussion:
106 comments Page 7 of 11.

Raji said:   1 decade ago
What is the difference between 2nd problem and 10th problem?

Ankush said:   1 decade ago
5/18 we can get like that.

Suppose speed is 10 km/hr so we can say like that.

(10)*1000/3600 m/second, so 1000/3600 will become 5/18.

Sushanto said:   1 decade ago
Why (36 x 5/18) is used? How you get 5/18?

Monica said:   1 decade ago
Why we add track length means because man is running on track? So man gets the track length.

Padma said:   1 decade ago
Question asked about at what time train cross man. Man has no length then why we add track length?

Ram said:   1 decade ago
Answer is 48 sec as jogger also jogs 2.5x distance.

= 360+2.5x/x = 10.

= 360+2.5x = 10x.

= 360 = 7.5x.

= 48 = x.

Hence 48 sec is the answer.

Prashant said:   1 decade ago
Please clear my doubt.

Let the train pass after t time.

So train has to cover (120+240+x)/45 in t time.

And jogger covers x/9 in t time.

(120+240+x) /45 = x/9.

Answer is 90 sec but logic is correct that they both meet after t time.

Atoria M. Horace said:   1 decade ago
I still can't understand how the 5/18 came about.

Ramsha said:   1 decade ago
Yes @Vedant, I also get the same answer through the same process.

Vedant said:   1 decade ago
@People considering distance traveled by jogger.

240 + 120 + 9*A (5/18) / (45*5/18) = A.

This will give A=36 so given solution is correct do no take relative speed concept just simply add distance to be covered and divide by train speed.


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