Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 10)
10.
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Answer: Option
Explanation:
Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.
= | ![]() |
36 x | 5 | ![]() |
18 |
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
![]() |
![]() |
360 | ![]() |
= 36 sec. |
10 |
Discussion:
106 comments Page 11 of 11.
Madhav Kulkarni said:
6 years ago
Speed of jogger=9km/h=9*(5/18)=2.5m/s.
Length=240.
Length of train = 120m.
Speed of train = 45km/h=45(5/18)=12.15m/s.
Relative Length=240+120=360m.
Relative speed=12.15-2.5=9.65m/s.
Speed = Distance/Time.
9.65 = 360/Time.
Time = 360/9.65.
= 36.
Length=240.
Length of train = 120m.
Speed of train = 45km/h=45(5/18)=12.15m/s.
Relative Length=240+120=360m.
Relative speed=12.15-2.5=9.65m/s.
Speed = Distance/Time.
9.65 = 360/Time.
Time = 360/9.65.
= 36.
Syrus said:
5 years ago
When the train is moving towards the jogger the jogger is still running at 9Kmph or 2.5 m/sec so by the time the engine reaches 240mtrs the jogger would've moved forward.
Time taken for front of train to cover 240 mtrs = 24 secs (time = distance / speed{relative = 10 m/s})
Also the distance travelled by jogger in this 24 secs is = 2.5 mtr/sec * 24 sec = 60 mtrs
so in order for the train to completely pass the jogger, it has to travel 60 mtrs more.
Total distance = 60 + 120 = 180 m.
Speed = 10 m/s.
Time = 18 sec.
Total time = 18 + 24 = 42 sec.
Is this method is correct?
Time taken for front of train to cover 240 mtrs = 24 secs (time = distance / speed{relative = 10 m/s})
Also the distance travelled by jogger in this 24 secs is = 2.5 mtr/sec * 24 sec = 60 mtrs
so in order for the train to completely pass the jogger, it has to travel 60 mtrs more.
Total distance = 60 + 120 = 180 m.
Speed = 10 m/s.
Time = 18 sec.
Total time = 18 + 24 = 42 sec.
Is this method is correct?
Chirag said:
4 years ago
Why we have taken the distance covered by train as (120m +240m)? why to add the length of the track? Please explain.
Kevin said:
4 years ago
The distance to be covered is the length from the train to the jogger (240) And we are adding 120 because we need to know the time when the whole train passes the jogger.
Dheeraj Shenoy said:
4 years ago
The jogger is running at 9kmph.
240m ahead from 120m long train.
When the train covers 240m at speed of 45kmph in t = 96/5 sec in the same time the jogger covers 48m.
Since he is jogging at a particular speed so the total distance covered by the train to pass the jogger would be 120+240+48.
Then, how it could be 240 +120?
240m ahead from 120m long train.
When the train covers 240m at speed of 45kmph in t = 96/5 sec in the same time the jogger covers 48m.
Since he is jogging at a particular speed so the total distance covered by the train to pass the jogger would be 120+240+48.
Then, how it could be 240 +120?
Bahu said:
3 years ago
Because if two trains run in the same direction the Speed of train will decrease to pass another train.
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