Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 10)
10.
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Answer: Option
Explanation:
Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.
= | ![]() |
36 x | 5 | ![]() |
18 |
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
![]() |
![]() |
360 | ![]() |
= 36 sec. |
10 |
Discussion:
106 comments Page 10 of 11.
Aditya bala said:
1 decade ago
We calculate relative speed for opposite and same direction if they travel in opposite direction we add them, in same direction we substract them.
Deepak agrawal said:
1 decade ago
@Harika
we calculate the ralative speed when two object are run simultenously in parallel .
we calculate the ralative speed when two object are run simultenously in parallel .
Viji.T said:
1 decade ago
The distance taken here is not clear for me. They use the term ahead of the engine like that. What they mean there. To take a distance as (120+240) , what is the logic behind that. Please can anyone explain me?
Harika said:
1 decade ago
When we have to calculate relative speed?
Viji said:
1 decade ago
Any body please explain that the relative speed calculation for both speed and distance when opposite and same direction moving ?
Gayathri said:
1 decade ago
Logic 1
Suppose two trains or two objects bodies are moving in the same direction at u m/s and v m/s, where u > v, then their relative speed is = (u - v) m/s.
Here the train moves at 45 km/hr and the jogger moves at 9 km/hr in same direction... relative speed = (45-9)= 36 km/hr and since the distance is in meters we have to convert the relative speed i.e 36 km/hr to meter/sec by multiplying 5/18.
therefore, relative speed = 36 * 5/18 = 10 m/sec
Logic 2
If two trains of length a metres and b metres are moving in the same direction at u m/s and v m/s, then:
The time taken by the faster train to cross the slower train = (a + b)/(u-v).
In this question the train moves 120 m and jogger moves 240 m
total distance = 120 + 240 = 360
now we know relative speed and distance, so we can easily compute time by applying the formula time = distance / speed
time = 360 / 10 = 36 secs
Hope u understood friends
Suppose two trains or two objects bodies are moving in the same direction at u m/s and v m/s, where u > v, then their relative speed is = (u - v) m/s.
Here the train moves at 45 km/hr and the jogger moves at 9 km/hr in same direction... relative speed = (45-9)= 36 km/hr and since the distance is in meters we have to convert the relative speed i.e 36 km/hr to meter/sec by multiplying 5/18.
therefore, relative speed = 36 * 5/18 = 10 m/sec
Logic 2
If two trains of length a metres and b metres are moving in the same direction at u m/s and v m/s, then:
The time taken by the faster train to cross the slower train = (a + b)/(u-v).
In this question the train moves 120 m and jogger moves 240 m
total distance = 120 + 240 = 360
now we know relative speed and distance, so we can easily compute time by applying the formula time = distance / speed
time = 360 / 10 = 36 secs
Hope u understood friends
(1)
Dheeraj said:
1 decade ago
@rprabha... no when two things are going in same direction then realtive speed is not sum of that things..
Sumi said:
1 decade ago
hi priyanka u understood wrongly relative speed for the objects in same direction is obtained by subtracting only
Jelli said:
1 decade ago
Hi
i think you can use the formula
u=(a+b)/(u-v) (both in a same dir)
=(120+240)/(45-9)*5/18
=36s
i think you can use the formula
u=(a+b)/(u-v) (both in a same dir)
=(120+240)/(45-9)*5/18
=36s
Priyanka said:
1 decade ago
Can you explain me why in this question relative speed is subtaction of higher speed to lower while in same direction relative speed is addition of both object speed?
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