Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
279 comments Page 8 of 28.
Jesudas said:
7 years ago
@Sagar Dombale.
It's the conversion of km/h to m/s.
It's the conversion of km/h to m/s.
Sagar Dombale said:
7 years ago
What is 5/18? Please explain me.
Somnath sen said:
7 years ago
Anyone Please explain it for me.
Harsh said:
7 years ago
I think the answer should be 540.
Because, how can the length of the platform be less than the length of the trian?
Because, how can the length of the platform be less than the length of the trian?
Manisha dambe said:
7 years ago
Time to pass platform = 16s,
length of platform=t*s,
= 16*54*5/18=245.
The length of platform=245 m.
length of platform=t*s,
= 16*54*5/18=245.
The length of platform=245 m.
Shivam singh said:
7 years ago
Km/h to m/s.
So,
54kmph = 54*5/18 = 15m/s.
The Length of platform = speed * time difference (because 20 is referral point)
= 15 * (36 - 20) = 240m.
So,
54kmph = 54*5/18 = 15m/s.
The Length of platform = speed * time difference (because 20 is referral point)
= 15 * (36 - 20) = 240m.
Kavya said:
7 years ago
Very good answer @Vetri.
Nisha said:
7 years ago
Thanks, @Vetri.
Er.Shubham said:
7 years ago
@Krishna,
Don't compare the Length of both.
Take only the starting and ending point.
Don't compare the Length of both.
Take only the starting and ending point.
Roshan said:
7 years ago
Sol: speed of train in m/sec = 54*5/18.
=15 m/sec.
The total Distance of both = speed * time.
Platform and train =15 * 36 m
= 540m
And the Length of train = 20 * 15 m.
= 300m.
Plateform=(total distance - length of the train).
= (540 - 300) m,
= 240 m.
=15 m/sec.
The total Distance of both = speed * time.
Platform and train =15 * 36 m
= 540m
And the Length of train = 20 * 15 m.
= 300m.
Plateform=(total distance - length of the train).
= (540 - 300) m,
= 240 m.
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