Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
285 comments Page 7 of 29.
Mahesh Kariya said:
6 years ago
(36-20)X(54X(5/18)) = 240.
Ganesh Babu Korlapati said:
7 years ago
Why we cannot take 15*36.
Because dist = speed x time know. 36seconds is also speed only know.
Because dist = speed x time know. 36seconds is also speed only know.
Sravana said:
7 years ago
D = TxS.
As we mentioned here,
54kmph = 54x(5÷18) = 15mps.
D = TxS.
= (36-20)x15.
= 16x15.
= 240mts.
As we mentioned here,
54kmph = 54x(5÷18) = 15mps.
D = TxS.
= (36-20)x15.
= 16x15.
= 240mts.
Cnine said:
7 years ago
The second method is, Convert the speed in m/sec.
And man is standing in platform then the both given time is subtract to each other and the subtract answer is multiplied the speed.
And man is standing in platform then the both given time is subtract to each other and the subtract answer is multiplied the speed.
Raghul said:
7 years ago
There is no length for man hence,
L/15 = 20.
L= 300.
And platform has length hence,
L+B/15 =36.
300+B = 540.
B=240.
L/15 = 20.
L= 300.
And platform has length hence,
L+B/15 =36.
300+B = 540.
B=240.
Kartik said:
7 years ago
54*5/18 = 15m/sec.
36-20 = 16 seconds.
Distance = speed *time.
Distance = 15m/sec*16 seconds.
Distance = 240m.
36-20 = 16 seconds.
Distance = speed *time.
Distance = 15m/sec*16 seconds.
Distance = 240m.
Shelke ganesh mariba said:
7 years ago
According to speed of trai = 15m/s.
And time = 36-20 = 16sec.
Therefore length of platform = 15x16 = 240m.
And time = 36-20 = 16sec.
Therefore length of platform = 15x16 = 240m.
Ramu said:
7 years ago
Any one please explain me.
Omkar Nivalagi said:
7 years ago
Simply;
Find speed in m/sec
54*(5/18).
And the difference between two lengths from plat1 to plat2 i,e (36-20)=16 and this is to the time taken to cross length plat1 to plat2 in secs.
As we know s=d/t;
5/18*16=240; answer
Find speed in m/sec
54*(5/18).
And the difference between two lengths from plat1 to plat2 i,e (36-20)=16 and this is to the time taken to cross length plat1 to plat2 in secs.
As we know s=d/t;
5/18*16=240; answer
Revanth said:
7 years ago
Given
t(p) =36s.
t(m)=20s.
Speed of the train = 54km/hr.
As we all know that speed = distance/ time.
Now, we have to convert the speed in m/s.
So, 54*5/18=15 m/s.
S=d/t => l/t.
L(t)= s*t => 15 m/s * 20s = 300m,
Now l(t)+l(b)= 15 m/s * 36s,
300m + l(b) = 540m.
L(b) = 540-300,
L(b)= 260 m.
t(p) =36s.
t(m)=20s.
Speed of the train = 54km/hr.
As we all know that speed = distance/ time.
Now, we have to convert the speed in m/s.
So, 54*5/18=15 m/s.
S=d/t => l/t.
L(t)= s*t => 15 m/s * 20s = 300m,
Now l(t)+l(b)= 15 m/s * 36s,
300m + l(b) = 540m.
L(b) = 540-300,
L(b)= 260 m.
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