Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
120 m
240 m
300 m
None of these
Answer: Option
Explanation:

Speed = 54 x 5 m/sec = 15 m/sec.
18

Length of the train = (15 x 20)m = 300 m.

Let the length of the platform be x metres.

Then, x + 300 = 15
36

x + 300 = 540

x = 240 m.

Discussion:
287 comments Page 26 of 29.

Manisha dambe said:   8 years ago
Time to pass platform = 16s,
length of platform=t*s,
= 16*54*5/18=245.
The length of platform=245 m.

Harsh said:   8 years ago
I think the answer should be 540.

Because, how can the length of the platform be less than the length of the trian?

Somnath sen said:   8 years ago
Anyone Please explain it for me.

Sagar Dombale said:   8 years ago
What is 5/18? Please explain me.

Jesudas said:   8 years ago
@Sagar Dombale.

It's the conversion of km/h to m/s.

Remee Rahul said:   7 years ago
Does the man standing on the starting/intial point of the platform?

Ramya said:   7 years ago
Please explain, how come 15*20?

Length of the train means we have to do 15*36, right?

Abhi singh said:   7 years ago
54 * 5/18 = 15.

You have values than 36-20 after you get=16, now
15*16 = 240m/s,
And this is easily finding your ans = 240m/s.

Suraj said:   7 years ago
Here, it is solved by taking 15*20 but why?

20 is speed of man not a train. We are taking into account that speed of train. If we take the speed of train then answer will becomes zero.

Vrunda savaliya said:   7 years ago
First substract time =36-20 = 16.
Then,
16 * 54 * 5/18.
Length = 240m.


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