Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
282 comments Page 25 of 29.
RAMKUMAR said:
8 years ago
Speed=54*5 ÷ 18=15.
:.15*20=300,
15*36=540,
--------------------
240.
Another option;
Speed 15.
36-20=16,
Therefore, 15 * 16 = 240.
:.15*20=300,
15*36=540,
--------------------
240.
Another option;
Speed 15.
36-20=16,
Therefore, 15 * 16 = 240.
Aryan said:
8 years ago
Why did they take 20 instead of 36?
Roshan said:
8 years ago
Sol: speed of train in m/sec = 54*5/18.
=15 m/sec.
The total Distance of both = speed * time.
Platform and train =15 * 36 m
= 540m
And the Length of train = 20 * 15 m.
= 300m.
Plateform=(total distance - length of the train).
= (540 - 300) m,
= 240 m.
=15 m/sec.
The total Distance of both = speed * time.
Platform and train =15 * 36 m
= 540m
And the Length of train = 20 * 15 m.
= 300m.
Plateform=(total distance - length of the train).
= (540 - 300) m,
= 240 m.
Er.Shubham said:
8 years ago
@Krishna,
Don't compare the Length of both.
Take only the starting and ending point.
Don't compare the Length of both.
Take only the starting and ending point.
Nisha said:
8 years ago
Thanks, @Vetri.
Kavya said:
8 years ago
Very good answer @Vetri.
Shivam singh said:
8 years ago
Km/h to m/s.
So,
54kmph = 54*5/18 = 15m/s.
The Length of platform = speed * time difference (because 20 is referral point)
= 15 * (36 - 20) = 240m.
So,
54kmph = 54*5/18 = 15m/s.
The Length of platform = speed * time difference (because 20 is referral point)
= 15 * (36 - 20) = 240m.
Manisha dambe said:
8 years ago
Time to pass platform = 16s,
length of platform=t*s,
= 16*54*5/18=245.
The length of platform=245 m.
length of platform=t*s,
= 16*54*5/18=245.
The length of platform=245 m.
Harsh said:
8 years ago
I think the answer should be 540.
Because, how can the length of the platform be less than the length of the trian?
Because, how can the length of the platform be less than the length of the trian?
Somnath sen said:
7 years ago
Anyone Please explain it for me.
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