Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Answer: Option
Explanation:
| Speed = |  |
45 x | 5 |  m/sec |
= | |
25 | m/sec. |
| 18 | 2 |
Time = 30 sec.
Let the length of bridge be x metres.
| Then, | 130 + x | = | 25 |
| 30 | 2 |
2(130 + x) = 750
x = 245 m.
Video Explanation: https://youtu.be/M_d8WufJWKc
Discussion:
249 comments Page 16 of 25.
Suren said:
1 decade ago
@Sai.
Your method is fantastic and very easy to understand. Great job! keep it up man. Thanks!
Your method is fantastic and very easy to understand. Great job! keep it up man. Thanks!
Sumit said:
8 years ago
@Guru.
5/18 is here because to converting distance km/h to m/s it's a formula to convert.
5/18 is here because to converting distance km/h to m/s it's a formula to convert.
Sarang said:
8 years ago
Distance = speed*time,
D= 45* 5/18*30,
D= 5*5/2* 30,
D= 5 * 5 * 15 = 375,
D= 375- 130= 245.
D= 45* 5/18*30,
D= 5*5/2* 30,
D= 5 * 5 * 15 = 375,
D= 375- 130= 245.
Sunny said:
2 decades ago
Hey boopathi its simple.
2(130+x)=750
130+x=750/2
130+x=375
x=375-130
Therefore x = 245.
2(130+x)=750
130+x=750/2
130+x=375
x=375-130
Therefore x = 245.
BLESINA DASARI said:
2 years ago
Solution:
45 * 5/18 = 12.5,
12.5 * 30 = 375,
375 - 130 = 245,
So, this is how we get 245.
45 * 5/18 = 12.5,
12.5 * 30 = 375,
375 - 130 = 245,
So, this is how we get 245.
(66)
Lokesh said:
1 decade ago
Actually bridge is a stationary object rite. So speed should be zero. Can u pls explain
Nitin said:
1 decade ago
Why we are subtracting 130 from 375. While train runs on the bridge not off the bridge?
RITESH said:
1 decade ago
I want to ask a simple question, how was to come 25/2 ? please send this answer ASAP.
Boopathi said:
2 decades ago
Hey how is it possible to come.
2 (130 + x) = 750.
X = 245 m.
Please advice me.
2 (130 + x) = 750.
X = 245 m.
Please advice me.
Nathy said:
1 decade ago
Sai's method of solving this problem is too simple and easy to understand. Thanks.
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