Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
200 m
225 m
245 m
250 m
Answer: Option
Explanation:

Speed = 45 x 5 m/sec = 25 m/sec.
18 2

Time = 30 sec.

Let the length of bridge be x metres.

Then, 130 + x = 25
30 2

2(130 + x) = 750

x = 245 m.

Video Explanation: https://youtu.be/M_d8WufJWKc

Discussion:
247 comments Page 16 of 25.

Sumit said:   8 years ago
@Guru.

5/18 is here because to converting distance km/h to m/s it's a formula to convert.

Sarang said:   7 years ago
Distance = speed*time,
D= 45* 5/18*30,
D= 5*5/2* 30,
D= 5 * 5 * 15 = 375,
D= 375- 130= 245.

Sunny said:   1 decade ago
Hey boopathi its simple.

2(130+x)=750
130+x=750/2
130+x=375
x=375-130

Therefore x = 245.

BLESINA DASARI said:   2 years ago
Solution:

45 * 5/18 = 12.5,
12.5 * 30 = 375,
375 - 130 = 245,
So, this is how we get 245.
(66)

Lokesh said:   1 decade ago
Actually bridge is a stationary object rite. So speed should be zero. Can u pls explain

Nitin said:   1 decade ago
Why we are subtracting 130 from 375. While train runs on the bridge not off the bridge?

RITESH said:   1 decade ago
I want to ask a simple question, how was to come 25/2 ? please send this answer ASAP.

Boopathi said:   1 decade ago
Hey how is it possible to come.

2 (130 + x) = 750.

X = 245 m.

Please advice me.

Nathy said:   1 decade ago
Sai's method of solving this problem is too simple and easy to understand. Thanks.

Siva Nandi Reddy said:   1 decade ago
Train length and bridge length is always add thats why we subtracted 130 from 375?


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