Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
200 m
225 m
245 m
250 m
Answer: Option
Explanation:

Speed = 45 x 5 m/sec = 25 m/sec.
18 2

Time = 30 sec.

Let the length of bridge be x metres.

Then, 130 + x = 25
30 2

2(130 + x) = 750

x = 245 m.

Video Explanation: https://youtu.be/M_d8WufJWKc

Discussion:
247 comments Page 15 of 25.

Imthiyaz ahmed said:   1 decade ago
25 meters per 2 sec, 1 sec = 12.5 *30sec = 375-130 = 245 very simple and very fast way to tackle the problem.

Akhil said:   9 years ago
Hi, can anyone tell me how to solve these type of problems?

I'm a just a beginner in maths. Please help me.

Joy said:   8 years ago
=> 45 * 5/18 = 225/18 m/s,
=> 225/18*30 = 375(train can go max distance in 30s).
=> 375-130 = 245.

Vaibhav mittal said:   8 years ago
Total distance covered by train in crossing the bridge = (25/2) *30=375.

Length of bridge = 375-130 =245.

Arman said:   9 years ago
In 30 second train goes= 45 x 1000 x 30 / 60 x 60 = 375 .

Bridge length = 375 - 130 = 245. Ans. 245.

Anu said:   9 years ago
130 + x/30 = 25/2.
2(130 + x) = 25 * 30,
260 + 2x = 750,
2x = 750-260,
2x = 490,
x = 490/2,
x = 245m.

Karthick said:   1 decade ago
Formula is = (Length of the train + Length of the object)=(Speed of the train* Time of the object).

Sundaram said:   1 decade ago
Because train cross the bridge so we must add the length then only we will get the bridge length.

Madhu said:   1 decade ago
We should convert km/hr to m/sec, so we should multiply the 45km/hr by 5/18,then we get 25m/sec.

Suren said:   1 decade ago
@Sai.

Your method is fantastic and very easy to understand. Great job! keep it up man. Thanks!


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