Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
200 m
225 m
245 m
250 m
Answer: Option
Explanation:

Speed = 45 x 5 m/sec = 25 m/sec.
18 2

Time = 30 sec.

Let the length of bridge be x metres.

Then, 130 + x = 25
30 2

2(130 + x) = 750

x = 245 m.

Video Explanation: https://youtu.be/M_d8WufJWKc

Discussion:
252 comments Page 17 of 26.

RITESH said:   1 decade ago
I want to ask a simple question, how was to come 25/2 ? please send this answer ASAP.

Boopathi said:   2 decades ago
Hey how is it possible to come.

2 (130 + x) = 750.

X = 245 m.

Please advice me.

Nathy said:   2 decades ago
Sai's method of solving this problem is too simple and easy to understand. Thanks.

Siva Nandi Reddy said:   1 decade ago
Train length and bridge length is always add thats why we subtracted 130 from 375?

Rajan said:   2 decades ago
Periyasamy is perfectly correct and is the correct logic to solve the problem.

Rohit said:   2 decades ago
For just above explanation, bridge end point means, departure point of bridge.

Sanjeev said:   9 years ago
Speed = 45 x 5/18 m/sec = 25/2 m/sec.

How it is calculated?

Please explain.

Kuma said:   8 years ago
Speed=Distance/Time.

45*5/18=Distance/30,
375= Distance,
Length= 375-130=245.

Jose said:   2 decades ago
Hey how is possible to come ?

2(130 + x) = 750

x = 245 m.

please advice me

Viji said:   1 decade ago
Vijay kumar your explanation is quite simple and understandable. Thank you.


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