Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 3)
3.
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Answer: Option
Explanation:
Speed = | ![]() |
45 x | 5 | ![]() |
= | ![]() |
25 | ![]() |
18 | 2 |
Time = 30 sec.
Let the length of bridge be x metres.
Then, | 130 + x | = | 25 |
30 | 2 |
2(130 + x) = 750
x = 245 m.
Video Explanation: https://youtu.be/M_d8WufJWKc
Discussion:
247 comments Page 17 of 25.
Rajan said:
1 decade ago
Periyasamy is perfectly correct and is the correct logic to solve the problem.
Rohit said:
1 decade ago
For just above explanation, bridge end point means, departure point of bridge.
Sanjeev said:
8 years ago
Speed = 45 x 5/18 m/sec = 25/2 m/sec.
How it is calculated?
Please explain.
How it is calculated?
Please explain.
Kuma said:
7 years ago
Speed=Distance/Time.
45*5/18=Distance/30,
375= Distance,
Length= 375-130=245.
45*5/18=Distance/30,
375= Distance,
Length= 375-130=245.
Jose said:
2 decades ago
Hey how is possible to come ?
2(130 + x) = 750
x = 245 m.
please advice me
2(130 + x) = 750
x = 245 m.
please advice me
Viji said:
1 decade ago
Vijay kumar your explanation is quite simple and understandable. Thank you.
Kriti said:
1 decade ago
@VINU
Exactly that would be the total distance travelled by train in 30 sec
Exactly that would be the total distance travelled by train in 30 sec
Rekha said:
9 years ago
Hii @Sai.
Why did you subtract the two things that is length and speed?
Why did you subtract the two things that is length and speed?
Swamy said:
10 years ago
Well,
36 sec --- 450 mt.
30 sec --- 375 mt.
Then, 375-135 = 275 mt.
36 sec --- 450 mt.
30 sec --- 375 mt.
Then, 375-135 = 275 mt.
Anonymous said:
1 day ago
I am not getting this answer. Anyone, please help me by explaining it.
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