Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 6)
6.
A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
Answer: Option
Explanation:
| Speed = |  |
240 |  m/sec = 10 m/sec. |
| 24 |
 Required time = |
|
240 + 650 | sec = 89 sec. |
| 10 |
Discussion:
202 comments Page 6 of 21.
Kishor said:
1 decade ago
For speed of the train (assume Z).
[distance = speed x time].
240 = Z x 24.
Z = 240/24.
Z = 10m/sec.
Let assume time is Y,
Length of the platform = (speed x time) - length of train.
650 = (10xY)-240.
Y = (650+240)/10.
Y = 89sec.
[distance = speed x time].
240 = Z x 24.
Z = 240/24.
Z = 10m/sec.
Let assume time is Y,
Length of the platform = (speed x time) - length of train.
650 = (10xY)-240.
Y = (650+240)/10.
Y = 89sec.
Rajesh lodhi said:
1 decade ago
Please solve this question.
A passenger train, 150m long.
Passage a railway platform 200 m long in 34 sec time taken by this train to pass a stationary man is.
Please help me anyone me to solve this question systematically.
A passenger train, 150m long.
Passage a railway platform 200 m long in 34 sec time taken by this train to pass a stationary man is.
Please help me anyone me to solve this question systematically.
Kirubanidhi said:
2 decades ago
First we find speed of the train
speed=distance/time ;distance=240m,time=24 sec
speed= 10 m/sec
the question is how long the train pass the 650m platform
so time = distance/speed;
=(240+650)/10 m/s
=89 sec
speed=distance/time ;distance=240m,time=24 sec
speed= 10 m/sec
the question is how long the train pass the 650m platform
so time = distance/speed;
=(240+650)/10 m/s
=89 sec
Pardhu said:
1 decade ago
Here train passing both the pole as well as the plate form ....
in question they clearly mentioned pole passing time in seconds only......
so we have to solve first 240/24 =10sec..
and than
(240+650/10)=890/10=89 sec.......
in question they clearly mentioned pole passing time in seconds only......
so we have to solve first 240/24 =10sec..
and than
(240+650/10)=890/10=89 sec.......
Bappy said:
9 years ago
As the length of trains is smaller than bridge so here train has to cover his as well as bridge distance. If the length of trains was bigger than platform then only by covering train's length platform length can be passed.
Smita said:
2 decades ago
I think this is simple
if
train 240 m long passes a pole in 24 seconds.
i.e 240 m : 24 sec
then 650 m : ? sec
and the ans is is 65sec
may this ans is also correct
will u plz explain why r u add 240& 650?
if
train 240 m long passes a pole in 24 seconds.
i.e 240 m : 24 sec
then 650 m : ? sec
and the ans is is 65sec
may this ans is also correct
will u plz explain why r u add 240& 650?
HARI said:
1 decade ago
Dudes,
Actually the length is calculated along with the train only as (650+240). The passing of the platform is for the train, so that, train tail has to pass the platform; Henceforth,
(Train+ Platform)is correct
Actually the length is calculated along with the train only as (650+240). The passing of the platform is for the train, so that, train tail has to pass the platform; Henceforth,
(Train+ Platform)is correct
Jawahar said:
1 decade ago
Answer should be 65. Because in question it doesn't mentioned as total time to cross. Question itself says that. I don't know why to add both. If they mentioned as "total time to cross" then the answer 89 is true.
Prakash said:
6 years ago
We add both the length of the train and platform because the train has to cross also its tail from the platform. If, the only head of train (engine) crosses the platform its other parts remain on the platform.
Rajesh said:
7 years ago
It should be 65 sec only.
Analysis: The speed of the train is the same in both cases. For the constant speed,
(distance/time) in first case = (distance/time) in second case.
240/24=650/x==> x = 65 sec.
Analysis: The speed of the train is the same in both cases. For the constant speed,
(distance/time) in first case = (distance/time) in second case.
240/24=650/x==> x = 65 sec.
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