Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 6)
6.
A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
65 sec
89 sec
100 sec
150 sec
Answer: Option
Explanation:

Speed = 240 m/sec = 10 m/sec.
24

Required time = 240 + 650 sec = 89 sec.
10

Discussion:
202 comments Page 6 of 21.

Ravinderreddy said:   1 decade ago
Why to add train length &platform length?

Sarah said:   1 decade ago
@Kirubanidhi

Thanks for the clear explanation.

Madhu said:   1 decade ago
Here starting position (source) is train length and ending position is platform length (destination) ok.

Pardhu said:   1 decade ago
Here train passing both the pole as well as the plate form ....
in question they clearly mentioned pole passing time in seconds only......
so we have to solve first 240/24 =10sec..
and than
(240+650/10)=890/10=89 sec.......

Pankaj said:   1 decade ago
Shouldn't it be 650+(240*2)?

Taj said:   1 decade ago
I'm so confused answer is 65 or 89.

If you sat 89 how it is come?

Kiran said:   1 decade ago
Guys I'm new to here can u ppl plz help....

Whyy can't i solve dis problem in disz way...

240 meters in 24 secs..
650 meters means ??

(650*24)/240 = 65 meters...

is this wrong ....

plzzz help me...

Koteswararao said:   1 decade ago
In order to determine the speed the distance of the train can we ignore the distance between the train and the pole.

Neetu said:   1 decade ago
We are adding 240 and 650 because the train needs to cross the entire platform. CROSSING means the last coach should cross the end of the platform. That's why we are adding both lenghts.

Kiran,

We cannot solve in your way because a train will never take the same time in crossing a pole and a platform. The train crossing the pole and crossing the platform is not same.

Pavan said:   1 decade ago
Pavan,

hello dudes there is a simple common sense
The length of the train is 240m
The length of the platform is 650m
So the total dstn to cross is (240+650)
=890m
ther fore
890/spd
=890/10
=89sec


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