Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 6)
6.
A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
Answer: Option
Explanation:
Speed = | ![]() |
240 | ![]() |
24 |
![]() |
![]() |
240 + 650 | ![]() |
10 |
Discussion:
202 comments Page 3 of 21.
Kumar said:
2 decades ago
Hi Saji,
You are wrong.
We have to add the length of the train to the length of the platform in order to find the time taken to 'cross the bridge'.
In case of crossing a man/post/pole:
Usually we will ignore the length of man/post/pole. If you want the result speed in 'milli meters/second' accuracy, you can add length of the man or pole to the length of the train.
You are wrong.
We have to add the length of the train to the length of the platform in order to find the time taken to 'cross the bridge'.
In case of crossing a man/post/pole:
Usually we will ignore the length of man/post/pole. If you want the result speed in 'milli meters/second' accuracy, you can add length of the man or pole to the length of the train.
(1)
Faruk said:
6 years ago
I think answer is 65 sec. Because there is not mention total time.
(1)
Mahesh Kariya said:
6 years ago
650/(240/24) = 65.
(1)
Laxman said:
5 years ago
Speed = distance/time.
240/24 m/sec =10 m/sec.
So required time is;
time = distance/speed.
= 240+650/10 sec.
= 89 sec.
240/24 m/sec =10 m/sec.
So required time is;
time = distance/speed.
= 240+650/10 sec.
= 89 sec.
(1)
Arbaz said:
4 years ago
@All.
When train at starting point of platform and its a start of train so remaining train is till not on platform so train will take platform length and train length too. That"s why we have to add both.
When train at starting point of platform and its a start of train so remaining train is till not on platform so train will take platform length and train length too. That"s why we have to add both.
(1)
Pachu said:
8 months ago
Given answer 89 is correct. I too agree.
(1)
JEYANTHI said:
2 decades ago
Since it passes both the poles and the platform , the distance been taken as 890m.(240+650)
Kirubanidhi said:
2 decades ago
First we find speed of the train
speed=distance/time ;distance=240m,time=24 sec
speed= 10 m/sec
the question is how long the train pass the 650m platform
so time = distance/speed;
=(240+650)/10 m/s
=89 sec
speed=distance/time ;distance=240m,time=24 sec
speed= 10 m/sec
the question is how long the train pass the 650m platform
so time = distance/speed;
=(240+650)/10 m/s
=89 sec
Aditya said:
2 decades ago
I think answer is 65 sec. Why did you add 240 and 650 no need to add?
Yuvi said:
2 decades ago
It may correct. 89sec.
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