Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 6)
6.
A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
65 sec
89 sec
100 sec
150 sec
Answer: Option
Explanation:

Speed = 240 m/sec = 10 m/sec.
24

Required time = 240 + 650 sec = 89 sec.
10

Discussion:
202 comments Page 10 of 21.

Arun said:   1 decade ago
I think that if they asked how long it will take to cross the pole and platform means 89 is correct but platform alone means 65 because speed of the trains 10m/s.

Lokesh said:   3 years ago
For 240m = 24sec.
==> 1m = 1/10 sec.

Total distance need to travel is (240+650) = 890m.
==>For 890m = 890/10 sec,
= 89Sec.
(9)

Himanshu said:   2 decades ago
Since the train has to cover the the length of the platform and its own distance..we have too take the total distance of platform and the length of train.

Faisal said:   9 years ago
The solution is correct.

If we don't add 240 we will get only the time taken for the engine to travel and not the entire train.

So we have to add it.

Jessie said:   1 decade ago
The question is how long the train takes to travel the platform. Then why do we add the train length here? can you please explain. Itz bit confusing.

Swetha said:   1 decade ago
Here no need of calculating the speed, as speed is same we can directly calculate as below:

(d1/t1) = (d2/t2).

(240/24) = ((240+650) /x).

X=89sec.

Divyan said:   1 decade ago
Why we can't minus 240 and 650. Please. Help me to know when should we add and when should we minus?

What is the meaning of engine crossing in 65?

Gaurav said:   1 decade ago
I think the data in not correct because they were asking to pass only 650m long. But here they are taken 650 + 240 which no where written to take.

PARAMESHWAR said:   3 years ago
I THINK ANS IS 65 SEC BECAUSE;

Directly calculate the answer;
240 = 24,
650 = X.

Cross multiplication.
240X = 15600.
X = 15600/240.
X = 65 Sec.
(46)

Nandhu said:   9 years ago
Pole:
Speed = lengh/time.
= 240/24,
= 10m/s.
Platform:

Time = length/speed.
= (240 + 650)/10,
= 89s.


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