Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 32 of 59.
Chithra said:
8 years ago
Thanks for all who have give explanation for this question, without your help I can't understand this problem.
Shoaib soudagar said:
8 years ago
You can simply solve like this.
1 0mtrs/1hr * second.
1000/60 * 9 = 150.
1 0mtrs/1hr * second.
1000/60 * 9 = 150.
Sazzad said:
8 years ago
Thanks a lot for the given explanation.
Siddhesh Anavkar said:
8 years ago
Formula.
1. Distance = speed * time
2. km/hr --> m/sec conversion
For ex. convert 90 km/hr to m/sec
Solution:-
90 km/1 hr = 90,000 m/3600 sec
= 25 m/sec.
1. Distance = speed * time
2. km/hr --> m/sec conversion
For ex. convert 90 km/hr to m/sec
Solution:-
90 km/1 hr = 90,000 m/3600 sec
= 25 m/sec.
Pinky said:
8 years ago
Can anyone explain me this step 60*5/18 =50/3?
Dorji said:
8 years ago
For (√(3N))^3/2=90.
I found N=134.44.
I found N=134.44.
Iqbal rasool said:
8 years ago
Nice and thank you sir.
Rahul Singh said:
7 years ago
Thanks for the explanation.
Asif Bilakhiya said:
7 years ago
Train Speed=60km/hr.
Take 9 seconds to cross the pole.
60km =60000 metres,
1hr=3600 seconds,
Ans=150 metres,
Explanation:
=(9x60000)/(3600),
=150 metres.
Take 9 seconds to cross the pole.
60km =60000 metres,
1hr=3600 seconds,
Ans=150 metres,
Explanation:
=(9x60000)/(3600),
=150 metres.
Vivek said:
7 years ago
We calculated the train length with reference to the pole. But what about the length of the pole. Doesn't it come to picture here?
Please, anyone, clarify it.
Please, anyone, clarify it.
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