Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
587 comments Page 31 of 59.
Kumar Verma said:
8 years ago
When we say a train passes a pole in given time then basically we consider that pole as stationary point (having 0 speed) whose length is zero means actually train crosses its own length in given time frame. If we say a running train passes another train (stationery or running) then we have to consider the total length of two trains crossing each other also we have to consider the relative speed of the trains if both trains are running in same direction then relative speed is the difference of their speed and if both are running in opposite direction then their relative speed is sum of their speed.
(1)
Sowmiya said:
8 years ago
Nice explanation, I understand your solution Thanks @Sundar.
Devkar Sunil said:
8 years ago
1hr(3600sec)=60 * 1000.
9sec=?.
Cross multipication =150m.
9sec=?.
Cross multipication =150m.
Santhosh said:
8 years ago
Nice explanation. Thanks.
Prasad said:
8 years ago
s=60*5/18,t=9;
s=d/t;
d=s*t=60*5/18*9=150;
s=d/t;
d=s*t=60*5/18*9=150;
Irine said:
8 years ago
I have one doubt.
Why don't you change 9sec into hours and then calculate distance?
Why don't you change 9sec into hours and then calculate distance?
Dileepkumar said:
8 years ago
Nice explanation.
Shwetha said:
8 years ago
Very nice explanation. Thank you all.
Raja tiwari said:
8 years ago
60*5÷18*9=150.
Deepanshu Sharma said:
8 years ago
Am i the only one who sucks in logic?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers