Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
120 metres
180 metres
324 metres
150 metres
Answer: Option
Explanation:

Speed = 60 x 5 m/sec = 50 m/sec.
18 3

Length of the train = (Speed x Time).

Length of the train = 50 x 9 m = 150 m.
3

Discussion:
587 comments Page 29 of 59.

Dileepkumar said:   8 years ago
Nice explanation.

Irine said:   8 years ago
I have one doubt.

Why don't you change 9sec into hours and then calculate distance?

Prasad said:   8 years ago
s=60*5/18,t=9;
s=d/t;
d=s*t=60*5/18*9=150;

Santhosh said:   8 years ago
Nice explanation. Thanks.

Devkar Sunil said:   8 years ago
1hr(3600sec)=60 * 1000.
9sec=?.
Cross multipication =150m.

Sowmiya said:   8 years ago
Nice explanation, I understand your solution Thanks @Sundar.

Kumar Verma said:   8 years ago
When we say a train passes a pole in given time then basically we consider that pole as stationary point (having 0 speed) whose length is zero means actually train crosses its own length in given time frame. If we say a running train passes another train (stationery or running) then we have to consider the total length of two trains crossing each other also we have to consider the relative speed of the trains if both trains are running in same direction then relative speed is the difference of their speed and if both are running in opposite direction then their relative speed is sum of their speed.
(1)

Subashini said:   8 years ago
1 km=3000m.
60 km=60000.
1 hr=3600sec,
=(60000/3600)*9,
=150m.

Priyanka said:   8 years ago
Very useful explanation. Thanks.

Gopi said:   8 years ago
Distance = Time *speed.
1km =1000Meteres,
1hr =3600 seconds,
Distance = 60*9/3600 =9/60 km,
Distane in Metres =(9/60)*1000 =150M.


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