Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 28 of 59.
Iqbal rasool said:
8 years ago
Nice and thank you sir.
Dorji said:
8 years ago
For (√(3N))^3/2=90.
I found N=134.44.
I found N=134.44.
Pinky said:
8 years ago
Can anyone explain me this step 60*5/18 =50/3?
Siddhesh Anavkar said:
8 years ago
Formula.
1. Distance = speed * time
2. km/hr --> m/sec conversion
For ex. convert 90 km/hr to m/sec
Solution:-
90 km/1 hr = 90,000 m/3600 sec
= 25 m/sec.
1. Distance = speed * time
2. km/hr --> m/sec conversion
For ex. convert 90 km/hr to m/sec
Solution:-
90 km/1 hr = 90,000 m/3600 sec
= 25 m/sec.
Sazzad said:
8 years ago
Thanks a lot for the given explanation.
Shoaib soudagar said:
8 years ago
You can simply solve like this.
1 0mtrs/1hr * second.
1000/60 * 9 = 150.
1 0mtrs/1hr * second.
1000/60 * 9 = 150.
Chithra said:
8 years ago
Thanks for all who have give explanation for this question, without your help I can't understand this problem.
Deepanshu Sharma said:
8 years ago
Am i the only one who sucks in logic?
Raja tiwari said:
8 years ago
60*5÷18*9=150.
Shwetha said:
8 years ago
Very nice explanation. Thank you all.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers