Aptitude - Problems on Trains - Discussion

I agree @Pradeep.

Really great explanation of the solution. Thank you all.

I easily understand the conversion. Thanks for the given explanations.

If you divide 1000/3600 = 0.27.

But it is showing 10/36 after that 5/18.

I am not understanding how it came 10/36 then 5/18?

Please help me by explaining it.

Thank you all, very nice explanations.

Many time we need to change speed from km/h to mtr/sec or mtr/sec to km/h. In the question, to change a speed from km/h to mtr/sec you have to multiply with 1000 and divide with 3600 and then u get speed in mtr/sec. For eg 90km/hr in mtr/sec?

We need to do 90*1000/3600 and u ll get 25m/s. because we do this mainly on every question. so we prepare ourselves in advance by cutting these two cake to serve immediately. Again same eg. 90k/h to m/s.
90 * 5/18 = 25 m/s.

And yes if we want to change m/s to k/h just multiply with 18/5 and you'll get your speed.
Eg. 25m/s to k/h ----25 * 18/5 = 90 k/h.

Length of a Train.

T = (LT+LP)/S
LT = LENGTH OF A TRAIN = ?
LP = LENGTH OF A PLATFORM = 0
S = SPEED = (60*5)/18 = 50/3
T= TIME= 9.

NOW AS PER THE QUESTION.

9 = (?+0)/ (50/3),
=> ? = (9 * 50)/3 = 150 M.

Train of length = x.
Speed of train is 60km/hr.
1km is 1000 * 60 =60000.
1hr is 60 minutes * 1hr =3600.
60000 ÷ 3600=16.6667.

Said that 9sec crosses a pole ,then
X = 16.667 * 9sec = 150m.
Distance = speed * time.

Good explanation. Thank you all.

Thanks for giving the explanation of the solution.