Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 27 of 59.
Suraj said:
9 years ago
Why it is divided by 5/18?
Sam prakash shine said:
9 years ago
@Suraj.
5/18 is for converting the km/hour into m/sec.
5/18 is for converting the km/hour into m/sec.
Manjesh said:
9 years ago
60 * 5/18 = 16.6666667. Then, Why it is divided by 50/3?
Siva said:
9 years ago
Can anybody tell me clearly how 50/3 m/sec came?
Pratiksha said:
9 years ago
It's really a nice explanation. It really helpful for beginners. I understood easily. Thank you all.
G hari krishna said:
9 years ago
You all converted km --> m. Why don't you convert seconds into hours?
Then S=d/t,
Then D=s*t.
But t=9 sec.
If we convert it into hours form we will get 1/400.
Then d=60*1/400.
Is it correct method. Let me explain in this way guys.
Then S=d/t,
Then D=s*t.
But t=9 sec.
If we convert it into hours form we will get 1/400.
Then d=60*1/400.
Is it correct method. Let me explain in this way guys.
Radhakrishnan L said:
9 years ago
Thank you for all your answers.
Mohd Siddique said:
9 years ago
Thanks for explanation.
Teja said:
9 years ago
@Sundar, @Kalimuthu & @Sungathan.
Really great explanation. Thank you all for your explanations.
Really great explanation. Thank you all for your explanations.
Dillip kumar said:
9 years ago
Well explained, Thanks @Sundar.
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