Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 22 of 59.
Sara said:
1 decade ago
Distance = Time *speed
1km =1000Meteres
1hr =3600 seconds
Distance = 60*9/3600 =9/60 km
Distane in Metres =(9/60)*1000 =150M
simple and fast way
1km =1000Meteres
1hr =3600 seconds
Distance = 60*9/3600 =9/60 km
Distane in Metres =(9/60)*1000 =150M
simple and fast way
Fuzail ahmad said:
1 decade ago
Very good to all.
Jayakumar said:
1 decade ago
Jayanthi, Sundar, Kalimuthu Thanks for a lot to YOU all
I can easily understand your problem solving system and it is not only useful to me but also to all thanks thanks thanks thanks thanks
I can easily understand your problem solving system and it is not only useful to me but also to all thanks thanks thanks thanks thanks
Baskar said:
1 decade ago
Any one know the how many feet is one meter? well explanations sundar.
Ajay said:
1 decade ago
Guy's why we multiply (speed x time) to find length.
train is going with 50/3 meter in one second,
suppose this train passes this pole in 1 second then train length would be 50/3 meter. (because 50/3 meter is covered by 1 second)
now suppose this train passes this pole in 2 second then train length would be (50/3)x 2 meter
now here train passes this pole in 9 second so the train length would be (50/3) x 9 = 150 meter
train is going with 50/3 meter in one second,
suppose this train passes this pole in 1 second then train length would be 50/3 meter. (because 50/3 meter is covered by 1 second)
now suppose this train passes this pole in 2 second then train length would be (50/3)x 2 meter
now here train passes this pole in 9 second so the train length would be (50/3) x 9 = 150 meter
Vikram said:
1 decade ago
Here,The Train speed =60km/1hr & That Train was crosses a one Pole in 9 Seconds.
So,Therefore we are converting Km into Meters And Hour into Seconds.....
i.e.,That train speed=60km/60Minute.
i.e.,that Train Speed=1km/1Minute.
and 1km=1000meters ,1Minute=60seconds.
So,The Train Length = 1Km/1Minute *9.
that means ,Length of Train=(1000/60)*9.
=150 Meters.
So,Therefore we are converting Km into Meters And Hour into Seconds.....
i.e.,That train speed=60km/60Minute.
i.e.,that Train Speed=1km/1Minute.
and 1km=1000meters ,1Minute=60seconds.
So,The Train Length = 1Km/1Minute *9.
that means ,Length of Train=(1000/60)*9.
=150 Meters.
Raja said:
1 decade ago
What is the shortcut method to calculate gcf of numbers?
Thangaraj K. said:
1 decade ago
Answer = sec/speed*1000 (i.e. - multiplied with 1000 to convert to metres )
=9/60*1000 = 150m
=9/60*1000 = 150m
Sai said:
1 decade ago
@SAI
Simply sperb
Simply sperb
Suresh said:
1 decade ago
Imagine the pole as a car moving on the train(road) which has a distance of 150m. If the pole(car) takes 9 sec to complete 150m, then what is the speed?
speed of the pole(car)=150m/9sec
= 16.67ms-1
=16.67*(18/5)km/hr
=60km/hr
speed of the pole(car)=150m/9sec
= 16.67ms-1
=16.67*(18/5)km/hr
=60km/hr
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