Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
626 comments Page 21 of 63.
SURAJ KUMAR RANA said:
3 months ago
Agree, the Answer is 150m.
(2)
Pallavi said:
2 weeks ago
The answer is 150m/s.
(2)
Jain Thomas said:
2 decades ago
Hi Sundar,
That was a damn good explanation
That was a damn good explanation
(1)
Parashuram said:
2 decades ago
How to calculate 16*5/18*9?
(1)
Soundhar said:
2 decades ago
Let length of the train be 'x' metres...
Speed of the train = 60km/hr(given)
Time = 9seconds(given)
refer the formulas for train problems...
As the time is given in seconds and answers are given in metre(train length) we are in need to convert from km/hr to m/s
km/hr = 1000m/(60min*60sec) = 5/18 m/s
Length of the train(distance covered a post)= speed * time
= (60*(5/18))*9
= (50/3)*9
= 150 m
For the train related formulas,check the READ MORE in Left corner(Important formulas)...
Speed of the train = 60km/hr(given)
Time = 9seconds(given)
refer the formulas for train problems...
As the time is given in seconds and answers are given in metre(train length) we are in need to convert from km/hr to m/s
km/hr = 1000m/(60min*60sec) = 5/18 m/s
Length of the train(distance covered a post)= speed * time
= (60*(5/18))*9
= (50/3)*9
= 150 m
For the train related formulas,check the READ MORE in Left corner(Important formulas)...
(1)
MATTA.SRINUVASRAO said:
2 decades ago
I'M UNDERSTAND SIR BUT I'm suppose to be confusing to seeing above following questions so I'm kindly requesting you to explain the solutions above question, thank you.
(1)
SANTOSH KUMAR M said:
1 decade ago
I'll Give Simple Logic Answer.
i.e.,
WKT,
Speed = Distance/Time.
So,
The speed of the train is given 60km/hr.
Convert Train Speed In meters and hours into Seconds.
That is,(60*1000)/(60min*60sec).
i.e.,1 km=1000m.
1 Hour=60min.
1 min= 60sec.
We get 16.67m/s.
That is, the train traveled 16.67 meters in 1 second.
Then multiply 9 seconds with 16.67 meters.
Then length of the train traveled 150 meters in 9 seconds.
i.e.,
WKT,
Speed = Distance/Time.
So,
The speed of the train is given 60km/hr.
Convert Train Speed In meters and hours into Seconds.
That is,(60*1000)/(60min*60sec).
i.e.,1 km=1000m.
1 Hour=60min.
1 min= 60sec.
We get 16.67m/s.
That is, the train traveled 16.67 meters in 1 second.
Then multiply 9 seconds with 16.67 meters.
Then length of the train traveled 150 meters in 9 seconds.
(1)
Rohit Sable said:
9 years ago
Thank you all, very nice explanations.
(1)
Kumar Verma said:
9 years ago
When we say a train passes a pole in given time then basically we consider that pole as stationary point (having 0 speed) whose length is zero means actually train crosses its own length in given time frame. If we say a running train passes another train (stationery or running) then we have to consider the total length of two trains crossing each other also we have to consider the relative speed of the trains if both trains are running in same direction then relative speed is the difference of their speed and if both are running in opposite direction then their relative speed is sum of their speed.
(1)
ALI AZAM said:
5 years ago
60km/hr convert into meters = 60*5/18 = 16.66 meter/sec.
This is for 1 second = 16.66 meter.
For 9 seconds just multiply by 9 = 16.66 * 9 = 150meter.
We already know that 1km/hr = 5/18meter/second.
1 meter/second = 18/5 km/hr.
This is for 1 second = 16.66 meter.
For 9 seconds just multiply by 9 = 16.66 * 9 = 150meter.
We already know that 1km/hr = 5/18meter/second.
1 meter/second = 18/5 km/hr.
(1)
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m/sec
Length of the train =