Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
608 comments Page 17 of 61.
Murali said:
3 years ago
Length = time/speed.
= 9sec/60kmhr.
= 0.15km = 150meter.
= 9sec/60kmhr.
= 0.15km = 150meter.
(49)
K Nithish said:
3 years ago
How come 5/18? Please explain me.
(67)
Nilesh avhad said:
3 years ago
600 % 36 = 16.67.
16.67 * 9 = 150.
16.67 * 9 = 150.
(13)
NARINDER KUMAR said:
3 years ago
9 = D*18/60 * 5 (USE S=D/T) AND (COVERT KM/HOUR IN TO M/SEC ) * 5/18.
So,
1 = D*2/300,
D = 300/2,
D = 150.
So,
1 = D*2/300,
D = 300/2,
D = 150.
(5)
Pavitra said:
3 years ago
1m = 1/1000km and
1s=1/3600hr.
So 1m/s = 3600/1000 = 18/5km/h.
1s=1/3600hr.
So 1m/s = 3600/1000 = 18/5km/h.
(30)
BikramTisso said:
3 years ago
Thanks for the explanation @Kenshika venistran.
(7)
Kenshika venistran said:
3 years ago
We know that 1 kilometre = 1000 meters and 1 hour = 3600 seconds.
Now, 1 km/h can also be written as 1000/3600: 1 (kilometre/hour) = 1000/3600 (meters/seconds).
So, this is the formula which is used to convert km/h to m/s.
On simplifying 1000/3600 further, we get 5/18.
Now, 1 km/h can also be written as 1000/3600: 1 (kilometre/hour) = 1000/3600 (meters/seconds).
So, this is the formula which is used to convert km/h to m/s.
On simplifying 1000/3600 further, we get 5/18.
(73)
Alavaala Praveen Kumar said:
3 years ago
60 * 5/18 = 50/3.
50/3 * 9,
Then 50 * 3,
Answer = 150.
50/3 * 9,
Then 50 * 3,
Answer = 150.
(15)
Jai said:
3 years ago
from the above statement:
60,000 m is crossed in=>3600 s.
? m is crossed in=> 9 s.
60000/x => 3600/9.
Do a normal cross-division method to find x. That's the answer.
60,000 m is crossed in=>3600 s.
? m is crossed in=> 9 s.
60000/x => 3600/9.
Do a normal cross-division method to find x. That's the answer.
(25)
Christo said:
3 years ago
The length of the train can be anything! why are we taking distance from the initial point to the pole?
Please explain.
Please explain.
(10)
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m/sec
Length of the train =