Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 11 of 59.
Teju said:
6 years ago
Speed of train: 60km/hr,
Train reaches the pole :9 sec,
Convert speed of Train from "Km/hr toM/sec,
60,000m/3600sec = 16.666 m/sec,
Length of train = 16.66*9 = 149.994M.
Train reaches the pole :9 sec,
Convert speed of Train from "Km/hr toM/sec,
60,000m/3600sec = 16.666 m/sec,
Length of train = 16.66*9 = 149.994M.
Pirakash said:
3 years ago
Simplest way,
Our train took 9 secs at 60 kmph.
Convert the time taken into hours ->. 0025 hrs.
So, distance (required length) = Speed x Time = 60 x. 0025 =. 15 km = 150 m.
Our train took 9 secs at 60 kmph.
Convert the time taken into hours ->. 0025 hrs.
So, distance (required length) = Speed x Time = 60 x. 0025 =. 15 km = 150 m.
(59)
Dadasaheb kamble said:
6 months ago
How 5/18 came I will explain.
1 km = 1000 m.
1hr = 60min.
1 min = 60sec.
60min = 3600 sec.
1000/3600 = 5/18.
(Cancelling two zeroes up and down and 2 * 5 = 10 and 2 * 18 = 36).
1 km = 1000 m.
1hr = 60min.
1 min = 60sec.
60min = 3600 sec.
1000/3600 = 5/18.
(Cancelling two zeroes up and down and 2 * 5 = 10 and 2 * 18 = 36).
(118)
Rasu said:
1 decade ago
Speed convert km/h to m/sec speed=[60*5/18]m/sec
speed=[50/3]m/sec.
Distance=[speed*time]
Length of the train=[50/3*9]
=150m.
speed=[50/3]m/sec.
Distance=[speed*time]
Length of the train=[50/3*9]
=150m.
Rahul said:
1 decade ago
We get 16.67m/s.
That is, the train traveled 16.67 meters in 1 second.
Then multiply 9 seconds with 16.67 meters.
Then length of the train traveled 150 meters in 9 seconds.
That is, the train traveled 16.67 meters in 1 second.
Then multiply 9 seconds with 16.67 meters.
Then length of the train traveled 150 meters in 9 seconds.
Micheal Raj P said:
3 years ago
60km is converted to 60000m and 1 hour to 3600sec, there for 60000/3600 answer to 16.66 and multiple to 9sec and answer is 149.999.
So, here, the full value as 150 metres.
So, here, the full value as 150 metres.
(1)
Mahalakshmi Chatrathi said:
2 years ago
60 km/hr = 60 * 1000m/60 * 60 = 50/3m/s.
#speed = distance/time,
1km = 1000m,
1hr = 60m&
1min = 60s.
Then Length(l) = speed * time
l = 50/3 * 9 = 1350/9.
l = 150m.
#speed = distance/time,
1km = 1000m,
1hr = 60m&
1min = 60s.
Then Length(l) = speed * time
l = 50/3 * 9 = 1350/9.
l = 150m.
(51)
Kusuma Kumari Neelam said:
6 months ago
How 5/18 came I will explain.
1 km = 1000 m.
1hr = 60min.
1 min = 60sec.
60min = 3600 sec.
1000/3600 = 5/18.
(Cancelling two zeroes up and down and 2*5 = 10 and 2*18=36).
1 km = 1000 m.
1hr = 60min.
1 min = 60sec.
60min = 3600 sec.
1000/3600 = 5/18.
(Cancelling two zeroes up and down and 2*5 = 10 and 2*18=36).
(24)
Ashura ram said:
2 years ago
60Km/hr.
1km = 1000m
1hr = 60min.
1sec = 60sec.
Got it.
1000 ÷ 60×60.
The Formula is
Distance=speed×Time
Listen here,
D = S×T,
S = 60,
T = 9.
60 × 5 ÷ 18 × 9.
[150m].
1km = 1000m
1hr = 60min.
1sec = 60sec.
Got it.
1000 ÷ 60×60.
The Formula is
Distance=speed×Time
Listen here,
D = S×T,
S = 60,
T = 9.
60 × 5 ÷ 18 × 9.
[150m].
(16)
Mandla kavitha said:
10 years ago
The speed of train is 60 km/h. Time taken by train is 9 sec.
Then length of train is (d = velocity*time).
(60*5)/18*9 =150 m.
Therefore;the length of train is 150 m.
Then length of train is (d = velocity*time).
(60*5)/18*9 =150 m.
Therefore;the length of train is 150 m.
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