Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
626 comments Page 11 of 63.
Hemanth said:
1 year ago
@All.
Let me explain in the short.
1st look at the options is in meters so 1 kms = 1000m.
1000/60 (speed) =16.66666 per sec,
Length = speed × time.
So, the answer is 16.6666 × 9 = 150m.
Let me explain in the short.
1st look at the options is in meters so 1 kms = 1000m.
1000/60 (speed) =16.66666 per sec,
Length = speed × time.
So, the answer is 16.6666 × 9 = 150m.
(148)
Kuldeep said:
1 decade ago
*Simple solution*
We know that,
1) 60km/1hr= 60000m/3600sec , (1hr=3600sec).
*Calulation = 60000/3600 = 16.66m/sec.
16.66x9 = 149.99 = 150m answer.
We know that,
1) 60km/1hr= 60000m/3600sec , (1hr=3600sec).
*Calulation = 60000/3600 = 16.66m/sec.
16.66x9 = 149.99 = 150m answer.
Hari mahe said:
9 years ago
That is (60 * (5/18) * 9) = 150.
Actually, the train speed is given in 60km/hour. We just convert that into m/sec as follows:
60km/hour = 60 * (5/18)m/sec that is equal to 150.
Actually, the train speed is given in 60km/hour. We just convert that into m/sec as follows:
60km/hour = 60 * (5/18)m/sec that is equal to 150.
Akshay Reddy said:
6 months ago
In there 1km = 1000m,
and 1hr = 3600sec.
Now we should use 1km/hr = 1000/3600;
In the above line, two zeroes are cancelled.
Then 10/36, and we use division, then it comes to 5/18.
and 1hr = 3600sec.
Now we should use 1km/hr = 1000/3600;
In the above line, two zeroes are cancelled.
Then 10/36, and we use division, then it comes to 5/18.
(18)
Sunil sharma said:
8 years ago
Tse speed of train 60km/h,
cross the poll with in 9 sec.
speed of train in 1 mint. = 1km,
Now, speed of train in 1 sec.= 1000/60= 16.67,
Now the length of train= 16.67*9 = 150 m.
cross the poll with in 9 sec.
speed of train in 1 mint. = 1km,
Now, speed of train in 1 sec.= 1000/60= 16.67,
Now the length of train= 16.67*9 = 150 m.
Palakananda said:
1 decade ago
Thanks for nice explanation you can solve same as followed.
Total exp = 15%+55% = 70%
Let salary Rs.100
Save = 100-70 = Rs.30%
Rs.30% = 12750.
100% = 12750/30x100 = 42500.
Total exp = 15%+55% = 70%
Let salary Rs.100
Save = 100-70 = Rs.30%
Rs.30% = 12750.
100% = 12750/30x100 = 42500.
Teju said:
6 years ago
Speed of train: 60km/hr,
Train reaches the pole :9 sec,
Convert speed of Train from "Km/hr toM/sec,
60,000m/3600sec = 16.666 m/sec,
Length of train = 16.66*9 = 149.994M.
Train reaches the pole :9 sec,
Convert speed of Train from "Km/hr toM/sec,
60,000m/3600sec = 16.666 m/sec,
Length of train = 16.66*9 = 149.994M.
Pirakash said:
4 years ago
Simplest way,
Our train took 9 secs at 60 kmph.
Convert the time taken into hours ->. 0025 hrs.
So, distance (required length) = Speed x Time = 60 x. 0025 =. 15 km = 150 m.
Our train took 9 secs at 60 kmph.
Convert the time taken into hours ->. 0025 hrs.
So, distance (required length) = Speed x Time = 60 x. 0025 =. 15 km = 150 m.
(59)
Dadasaheb kamble said:
1 year ago
How 5/18 came I will explain.
1 km = 1000 m.
1hr = 60min.
1 min = 60sec.
60min = 3600 sec.
1000/3600 = 5/18.
(Cancelling two zeroes up and down and 2 * 5 = 10 and 2 * 18 = 36).
1 km = 1000 m.
1hr = 60min.
1 min = 60sec.
60min = 3600 sec.
1000/3600 = 5/18.
(Cancelling two zeroes up and down and 2 * 5 = 10 and 2 * 18 = 36).
(119)
Rasu said:
1 decade ago
Speed convert km/h to m/sec speed=[60*5/18]m/sec
speed=[50/3]m/sec.
Distance=[speed*time]
Length of the train=[50/3*9]
=150m.
speed=[50/3]m/sec.
Distance=[speed*time]
Length of the train=[50/3*9]
=150m.
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