Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 8)
8.
A number consists of two digits. If the digits interchange places and the new number is added to the original number, then the resulting number will be divisible by:
Answer: Option
Explanation:
Let the ten's digit be x and unit's digit be y.
Then, number = 10x + y.
Number obtained by interchanging the digits = 10y + x.
(10x + y) + (10y + x) = 11(x + y), which is divisible by 11.
Video Explanation: https://youtu.be/lytJE8GqRvM
Discussion:
20 comments Page 1 of 2.
Krishna said:
1 decade ago
Two digits No. means any of the number from 10 to 99.
let us take 98 as a 2 digit number. In this number 9 tens and one 8 is there. 9 tens means 9x10. that is 90 and one 8 is being added. So that we can get 98.
That is why they have mentioned as ten's digit.
for your understanding we will take a 98743265.
In this number 5 is in the place of one, 6 is 10th, 2 is 100th, 3 is 1000th, 4 is 10,000th,7 is 1,00,000th 8 is 10,00,000th and 9 is 1,00,00,000th.
let us take 98 as a 2 digit number. In this number 9 tens and one 8 is there. 9 tens means 9x10. that is 90 and one 8 is being added. So that we can get 98.
That is why they have mentioned as ten's digit.
for your understanding we will take a 98743265.
In this number 5 is in the place of one, 6 is 10th, 2 is 100th, 3 is 1000th, 4 is 10,000th,7 is 1,00,000th 8 is 10,00,000th and 9 is 1,00,00,000th.
Anitha Karrre said:
5 years ago
@Ramya Sana.
Of course, your answer is right but while we dividing a number whether it is the small or big number we will choose the nearest divisor it makes easily.
Suppose, 99/3=33 & again we are dividing 33 by 3 so its very complex right. So that's why we are going take the nearest number which is divisible by that number.
Of course, your answer is right but while we dividing a number whether it is the small or big number we will choose the nearest divisor it makes easily.
Suppose, 99/3=33 & again we are dividing 33 by 3 so its very complex right. So that's why we are going take the nearest number which is divisible by that number.
(1)
Sajid said:
1 decade ago
10 to 99.
10, 11, 12, 13, 14, 15, 16, 17.......
10+01=11; 12+21=33; 13+31=44; 14+41=55.
Eg: 28+82=110;
Any two numbers from 10 to 99 gets interchange of 10 unit position to one unit position and one unit position to 10 unit position and do sum of the numbers that particular number will be definitely divisible 11.
10, 11, 12, 13, 14, 15, 16, 17.......
10+01=11; 12+21=33; 13+31=44; 14+41=55.
Eg: 28+82=110;
Any two numbers from 10 to 99 gets interchange of 10 unit position to one unit position and one unit position to 10 unit position and do sum of the numbers that particular number will be definitely divisible 11.
Pooja P Kumar said:
8 years ago
@Yogita.
Whenever the product of two numbers is asked.
For example: The product of two number is such that the result is 5.. so we will take same variables i.e x because x*5/x is 5. And mostly in all other cases, we will take two variables x and y.
Whenever the product of two numbers is asked.
For example: The product of two number is such that the result is 5.. so we will take same variables i.e x because x*5/x is 5. And mostly in all other cases, we will take two variables x and y.
Annah said:
8 years ago
(10x+y) + (10y + x)=
For; (10x+y)
Let x be 2and y be 1, substitute in 10x +y,
(10*2) + 1=21.
For; (10y+ x) interchange.
Let x be 2 and y be 1, substitute in (10y+x),
(10*1)+ 2=12.
Then, 12+ 21=33 which is divisible by 11.
For; (10x+y)
Let x be 2and y be 1, substitute in 10x +y,
(10*2) + 1=21.
For; (10y+ x) interchange.
Let x be 2 and y be 1, substitute in (10y+x),
(10*1)+ 2=12.
Then, 12+ 21=33 which is divisible by 11.
Ramya sana said:
7 years ago
For example if we take 27 and when we reverse it, we will get 72 and addition of these two numbers is 99 which will also divisible by 3 and 9 and 11. Then what is the answer. Anybody can help me out?
(2)
Kunal said:
10 years ago
If we take the no as 99. After reversing the no stays as 99.
Then new no added to original no, we get 99+99 = 198. 198 is divisible by 9 as well as 11.
So can anyone help out about this doubt.
Then new no added to original no, we get 99+99 = 198. 198 is divisible by 9 as well as 11.
So can anyone help out about this doubt.
Hemanth said:
1 decade ago
It is very easy,
Check with answer, in answer two-digit number is 11.
Then interchange it will '11'.
Then add old and new is = 11+11 = 22.
Sum:22, check with choice 22 is divisible by 11.
Check with answer, in answer two-digit number is 11.
Then interchange it will '11'.
Then add old and new is = 11+11 = 22.
Sum:22, check with choice 22 is divisible by 11.
Pattan Bajibabu said:
4 years ago
This very easy;
First, we take two-digit number I am take two digit number is 10,
Interchange positions 01,
Add the values 10+01=11,
So 11 is divisible by 11,
So, the answer is 11.
First, we take two-digit number I am take two digit number is 10,
Interchange positions 01,
Add the values 10+01=11,
So 11 is divisible by 11,
So, the answer is 11.
(13)
Sarika said:
1 decade ago
Take any two numbers. For ex take 63+36=99. So 99 is divisible by 11. If we take any two numbers all that numbers are only divisible by 11 only. So answer is 11.
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