Aptitude - Problems on Numbers - Discussion

Discussion Forum : Problems on Numbers - General Questions (Q.No. 8)
8.
A number consists of two digits. If the digits interchange places and the new number is added to the original number, then the resulting number will be divisible by:
3
5
9
11
Answer: Option
Explanation:

Let the ten's digit be x and unit's digit be y.

Then, number = 10x + y.

Number obtained by interchanging the digits = 10y + x.

(10x + y) + (10y + x) = 11(x + y), which is divisible by 11.

Video Explanation: https://youtu.be/lytJE8GqRvM

Discussion:
20 comments Page 2 of 2.

Virendra said:   1 decade ago
Like santosh it is really simple just start by taking
12....21.,
at first attempt option 5 and 9 cancelled out
at second attempt 13....31 we get ans is 11.

Ashish singh said:   1 decade ago
Very easy yar.

Take 10,11,......99 any number.
Just interchange position then add it,
Say 23+32 = 55.
24+42 = 66.
10+01 =11.
45+54 = 99.

Santhosh said:   1 decade ago
It's very simple..
for example take a two digit number : i.e 45
the reverse of the number is 54

So 45+54= 99(which is a divisible of 11)

Yogita said:   9 years ago
@Santhosh.

I'm pretty confused that when we have to take x, y, and when it is only x for the formation of two digit number?

Nikunjjain said:   1 decade ago
Why did they take ten digits number in the solution of question because in question they have mentioned 2 digits no ?

Santosh h said:   9 years ago
11 = 10x+y = 10(1)+1.

Another ex: 25=10x+y = 10(2)+5.

Also: 255=100x+10y+z = 100(2)+10(5)+5.

Raja said:   10 years ago
Simple answer.

10 = x.

y = "1" for example.

10x+y = 11.

11 is a answer. So option is D.

Vinay said:   10 years ago
When Should we take a 2 digit as 10x+y. And when should we take as x+y? Anybody help?

Suja said:   1 decade ago
Wow karishma yaar you are so talented sahi samzaya answer.

Now I got it.

Farukh said:   1 decade ago
I didn't get it.

Can anyone explain ?

Please.


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