Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)
2.
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
Answer: Option
Explanation:
Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 
x = 11.
Third integer = x + 4 = 15.
Video Explanation: https://youtu.be/_77C9YE321Y
Discussion:
75 comments Page 6 of 8.
Santhosh said:
1 decade ago
Rahman is right.
Because the given numbers should be odd numbers.
So we have to take...the three consecutive odd numbers as 2x+1, 2x+3, 2x+5
Because the given numbers should be odd numbers.
So we have to take...the three consecutive odd numbers as 2x+1, 2x+3, 2x+5
Md. Saifur Rahman said:
1 decade ago
2x+1, 2x+3, 2x+5
3(2x+1)=2(2x+5)+3
... x=5
(2x+5)=15
3(2x+1)=2(2x+5)+3
... x=5
(2x+5)=15
FRANCO said:
1 decade ago
The first part is 3 more than the second part.
So to equate it we have to add 3 to the second part
I part = II part + 3
The ans 15 is correct
So to equate it we have to add 3 to the second part
I part = II part + 3
The ans 15 is correct
Nishanthi said:
1 decade ago
Here 3 more than that of the value of x so we use.
3x=2 (x+4) +3, 0 is odd or even number so in this problem 0 is used.
3x=2 (x+4) +3, 0 is odd or even number so in this problem 0 is used.
Bharghavi said:
1 decade ago
The answer would be 9.
Explanation:
Suppose 3 nos. are x,x+2,x+4
The equations would be
3x+3=2(x+4),therefore x=5
So, the third no. is x+4=5+4=9.
Explanation:
Suppose 3 nos. are x,x+2,x+4
The equations would be
3x+3=2(x+4),therefore x=5
So, the third no. is x+4=5+4=9.
Sandeep pote said:
1 decade ago
Third integer would be 9.
Explanation:
Suppose 3 numbers are . . x, x+2, x+4.
3x = 2(x + 4) - 3
3x = 2x + 8 -3
x = 5
Then third number is 5 + 4 = 9.
Explanation:
Suppose 3 numbers are . . x, x+2, x+4.
3x = 2(x + 4) - 3
3x = 2x + 8 -3
x = 5
Then third number is 5 + 4 = 9.
Nilesh said:
1 decade ago
0 is considerd as even number.
Cutie said:
1 decade ago
2x+1, 2x+3, 2x+5 is the correct form.
Ssgm said:
1 decade ago
An integer n any odd will be (2n+1).
After (2n+1) is (2n+3) then (2n+5).
From the Q:
3(2n+1) > 2(2n+5).
=> n > 3.5 => n start from 4 to infinity.
So the numbers (2(4)+1=9), 11, 13 and I say the answer is 13.
After (2n+1) is (2n+3) then (2n+5).
From the Q:
3(2n+1) > 2(2n+5).
=> n > 3.5 => n start from 4 to infinity.
So the numbers (2(4)+1=9), 11, 13 and I say the answer is 13.
V.Ranjitha said:
1 decade ago
Hi friends,
I think Govind is correct. Because the x value may be odd number or even number.(2x+1,2x+3,2x+5)
If x=0,
We get 1, 3, 5.
If x=1(odd),
We get 3, 5, 7.
If x=2(even),
We get 5, 7, 9.
I think Govind is correct. Because the x value may be odd number or even number.(2x+1,2x+3,2x+5)
If x=0,
We get 1, 3, 5.
If x=1(odd),
We get 3, 5, 7.
If x=2(even),
We get 5, 7, 9.
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