Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 14)
14.
The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:
Answer: Option
Explanation:
L.C.M. of 5, 6, 7, 8 = 840.
Required number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2.
Required number = (840 x 2 + 3) = 1683.
Discussion:
86 comments Page 8 of 9.
Amendra said:
6 years ago
How does the value of k equals 2?
Sudip said:
7 years ago
Thanks for the answer @Suchita.
Priya said:
1 decade ago
nice Suchita ......it was nice
Rohit said:
10 years ago
Please help me how we get k=2?
Shariq said:
1 decade ago
Just divide all options by 9.
Ramya said:
1 decade ago
Why we are using variable k?
Gowtham said:
7 years ago
Well said, thanks @Suchita.
JITENDRA KUMAR said:
6 years ago
What is the Value of k?
Chinmaya said:
1 decade ago
How you will get 2 ?
M.V.KRISHNA/PALVONCHA said:
1 decade ago
Excellent suchita.
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