Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 14)
14.
The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:
Answer: Option
Explanation:
L.C.M. of 5, 6, 7, 8 = 840.
Required number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2.
Required number = (840 x 2 + 3) = 1683.
Discussion:
86 comments Page 7 of 9.
Kiruthikabaskaran said:
8 years ago
Super shorcut method. Thank you so much @Suchita.
Akshay said:
9 years ago
Please tell me, how to find the value of k?
Vijay said:
9 years ago
Please tell me how you put the value k=2?
Manikanta said:
9 years ago
@Itsnoble.
111111111 is divisible by 9.
111111111 is divisible by 9.
Revathi said:
5 years ago
840k+3 can anybody explain this step?
(9)
Ram said:
7 years ago
Thanks for the explanation @Suchita.
Nancy said:
6 years ago
I can't understand how k=2? Explain.
(2)
Tg said:
7 years ago
2 has come because 5*6*7*8 is 1683.
Renu said:
7 years ago
Good explanation, Thanks @Suchita.
Emu said:
1 decade ago
suchita it"s working.........
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