Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 14)
14.
The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:
Answer: Option
Explanation:
L.C.M. of 5, 6, 7, 8 = 840.
Required number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2.
Required number = (840 x 2 + 3) = 1683.
Discussion:
86 comments Page 9 of 9.
Kannan said:
6 years ago
How k= 2? Explain.
Nitesh said:
8 years ago
Thanks @Suchita.
Simanta said:
1 decade ago
Nice suchita !
Pankaj said:
1 decade ago
Nice Suchita.
Truptti said:
10 years ago
How get 840?
Sakshi said:
1 decade ago
nice Mehar.
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