Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 10)
10.
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
Answer: Option
Explanation:
L.C.M. of 6, 9, 15 and 18 is 90.
Let required number be 90k + 4, which is multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4.
Required number = (90 x 4) + 4 = 364.
Discussion:
88 comments Page 1 of 9.
Bhavesh said:
4 years ago
90K+4 is the required number.
If K=1,
90*1+4=94 , it is not multiple of 7.
90*2+4=184,it is not multiple of 7,
90*3+4=274,it is not multiple of 7,
90*4+4=364,it is multiple of 7,
So, the least value will be 364.
If K=1,
90*1+4=94 , it is not multiple of 7.
90*2+4=184,it is not multiple of 7,
90*3+4=274,it is not multiple of 7,
90*4+4=364,it is multiple of 7,
So, the least value will be 364.
(61)
Nakum pragnesh said:
3 years ago
Or which option is divisible by 7 is your answer
(23)
Sagar Khare said:
4 years ago
@ALL.
Guys here you use divisibility rules.
We have to find 7 multiple so apply the simple divisibility rule of 7 on all the answers.
Guys here you use divisibility rules.
We have to find 7 multiple so apply the simple divisibility rule of 7 on all the answers.
(23)
Navnath said:
4 years ago
As sample as that.
If the number is multiple of 7 then Obviously it should divide by 7.
Then check all the options by dividing 7.
Look only one option that is 364 is completely divided by 7.
If the number is multiple of 7 then Obviously it should divide by 7.
Then check all the options by dividing 7.
Look only one option that is 364 is completely divided by 7.
(22)
Jeni said:
5 years ago
6 = 2,3.
9 = 3,3.
15 = 3,5.
18 = 2,3,3.
LCM = 7 x 2 x 3 x 3 x 5 = 360.
Add the reminder = 360 + 4 = 364.
9 = 3,3.
15 = 3,5.
18 = 2,3,3.
LCM = 7 x 2 x 3 x 3 x 5 = 360.
Add the reminder = 360 + 4 = 364.
(21)
MMTbelieve youtube said:
2 years ago
We got till lcm 90 ,
Then N=90k+4 should be divisible by 4 then we will get n.
So, put k=1,2,3,4 on 4 the ans 364 is divisible by 7.
So N = 364.
Then N=90k+4 should be divisible by 4 then we will get n.
So, put k=1,2,3,4 on 4 the ans 364 is divisible by 7.
So N = 364.
(15)
Jambay said:
5 years ago
Why we are taking LCM instead of GCF? Please explain.
(7)
Akash said:
4 years ago
@Jeni.
Can you please explain how came 7 when calculating the LCM?
Can you please explain how came 7 when calculating the LCM?
(4)
SUBHANKAR DAS said:
4 years ago
L.C.M. of 6, 9, 15, and 18 is 90.
Let the required number be 90k + 4, which is a multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4,as it is not divisible if k=1,2,3
So, the Required number = (90 x 4) + 4 = 364.
Let the required number be 90k + 4, which is a multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4,as it is not divisible if k=1,2,3
So, the Required number = (90 x 4) + 4 = 364.
(3)
Codi said:
3 years ago
Thanks for explaining @Rahul.
(2)
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