Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 10)
10.
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
Answer: Option
Explanation:
L.C.M. of 6, 9, 15 and 18 is 90.
Let required number be 90k + 4, which is multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4.
Required number = (90 x 4) + 4 = 364.
Discussion:
88 comments Page 2 of 9.
Aditya Kulkarni said:
6 years ago
@All.
Here, We have been asked for a least multiple of 7, therefore one of the numbers given in option must be divided by 7.
74, 94 and 184 are not divisible by 7, but 364 is. So, 364 is the answer.
Here, We have been asked for a least multiple of 7, therefore one of the numbers given in option must be divided by 7.
74, 94 and 184 are not divisible by 7, but 364 is. So, 364 is the answer.
(1)
Tushar said:
6 years ago
L.C.M. of 6, 9, 15 and 18 is 90.
Let the required number be 90k + 4, which is multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4.
Required number = (90 x 4) + 4 = 364.
90K+4 is the required no.
How?
If K=1
90*1+4=94 , it is not multiple of 7.
90*2+4=184, it is not multiple of 7.
90*3+4=274, it is not multiple of 7.
90*4+4=364, it is multiple of 7.
So the least value will be 364.
Let the required number be 90k + 4, which is multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4.
Required number = (90 x 4) + 4 = 364.
90K+4 is the required no.
How?
If K=1
90*1+4=94 , it is not multiple of 7.
90*2+4=184, it is not multiple of 7.
90*3+4=274, it is not multiple of 7.
90*4+4=364, it is multiple of 7.
So the least value will be 364.
(1)
Nagesh Bhukya said:
6 years ago
K = 4.
Because this value decided by 7 in 90k+4.
90(4)+4=364/7 = 52.
Remainder is 0 .
So k = 4 is correct.
Because this value decided by 7 in 90k+4.
90(4)+4=364/7 = 52.
Remainder is 0 .
So k = 4 is correct.
(1)
Choudhary said:
6 years ago
What if the value of k has very large?
(1)
Shakir said:
7 years ago
Here you can check from option also which is divisible of 7 like;
74 is not completely divided by 7.
Same as 94 and 184 also, But 364 is completely divisible by 7, So 364 is the answer.
74 is not completely divided by 7.
Same as 94 and 184 also, But 364 is completely divisible by 7, So 364 is the answer.
(1)
Prince said:
8 years ago
@Priya it is so easy.
6 = 2 * 3
9 = 3 * 3
15 = 3 * 5
18 = 2 * 3 * 3.
Take one number from common multiple and multiply rest digits.
2*3*3*5.
6 = 2 * 3
9 = 3 * 3
15 = 3 * 5
18 = 2 * 3 * 3.
Take one number from common multiple and multiply rest digits.
2*3*3*5.
Ritu said:
9 years ago
But why to do lcm of 6, 9, 15, 18 here?
Will somebody help me out?
Will somebody help me out?
Chanchal said:
8 years ago
90k + 4/7 find k.
90k/7 + 4/7.
We have to distribute 90 k as multiple of 7 and divisible by 7.
12 * 7k + 6k + 4/7.
12 * 7k/7 + 6k + 4/7.
Now we can put the value of k in 6k+4/7.
90k/7 + 4/7.
We have to distribute 90 k as multiple of 7 and divisible by 7.
12 * 7k + 6k + 4/7.
12 * 7k/7 + 6k + 4/7.
Now we can put the value of k in 6k+4/7.
Priya said:
9 years ago
How Lcm of 90 come? Please explain.
Ananya said:
8 years ago
Hey guys, what will we take in the right-hand side? Please help me out.
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