Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 12)
12.
The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:
3
13
23
33
Answer: Option
Explanation:

L.C.M. of 5, 6, 4 and 3 = 60.

On dividing 2497 by 60, the remainder is 37.

Number to be added = (60 - 37) = 23.

Discussion:
40 comments Page 3 of 4.

Umar said:   10 years ago
41.6166666 is not the remainder, it is the quotient. Divide it without using calculator by simple division method.

60)2497(41
    240
    ----
    97
    60
    ----
    37 is the remainder.

Poonam said:   1 decade ago
What would have been the case if we are asked to find the highest no. Which should be added to 2497?

Then are we supposed to add 37 to 2497 ?

Nimmi said:   1 decade ago
Why 2497 has been divided by 60? please explain completely.

Younus said:   1 decade ago
I want to know that why 2497 has been divided by 60? please elaborate.

Gautam said:   1 decade ago
The remainder is 37 how its come ? we divide but not come.

Gogol said:   1 decade ago
Why 60 has to be substracted from 37?

Shrabana said:   1 decade ago
Why should we divide 2497 by 60?

Chipmunk said:   1 decade ago
LCM is 60.
The sum is of the form 60k.
i.e. 2497 + n = 60k

Try through the options:
A]3
2497+3= 2500. It is not divisible by 60.
B]13
2497+13= 2510. It is not divisible by 60.
C]23
2497+23= 2520. It is divisible by 60.

The least no is asked so no need 2 try the D option.

Now this sum of 2520 is divisible by 60. So we added 23 to the given no 2497 so that the sum is divisible by all the nos 5,6,4 & 3.

Gannu said:   1 decade ago
@Prashanthy K.

Like 2497/60 does give 37 as remainder so that doesn't mean that it contains 37 60's because 37x60 \= 2497.

It is remainder, not quotient.

Can anyone explain why 60-37.

Parades said:   1 decade ago
How did in 60?


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