Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 12)
12.
The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:
3
13
23
33
Answer: Option
Explanation:

L.C.M. of 5, 6, 4 and 3 = 60.

On dividing 2497 by 60, the remainder is 37.

Number to be added = (60 - 37) = 23.

Discussion:
40 comments Page 1 of 4.

Nitin said:   1 decade ago
Great work Boss!!!!!!

Nimmi said:   1 decade ago
Why 2497 has been divided by 60? please explain completely.

Younus said:   1 decade ago
I want to know that why 2497 has been divided by 60? please elaborate.

Gautam said:   1 decade ago
The remainder is 37 how its come ? we divide but not come.

Gogol said:   1 decade ago
Why 60 has to be substracted from 37?

Shrabana said:   1 decade ago
Why should we divide 2497 by 60?

Chipmunk said:   1 decade ago
LCM is 60.
The sum is of the form 60k.
i.e. 2497 + n = 60k

Try through the options:
A]3
2497+3= 2500. It is not divisible by 60.
B]13
2497+13= 2510. It is not divisible by 60.
C]23
2497+23= 2520. It is divisible by 60.

The least no is asked so no need 2 try the D option.

Now this sum of 2520 is divisible by 60. So we added 23 to the given no 2497 so that the sum is divisible by all the nos 5,6,4 & 3.

Prashanthy K said:   1 decade ago
very simple

Look 60 is the common number divisible by 5,6,4& 3
ie LCM of 5,6,4,3

now when we divide 2497/60, we get 37
That means 2497 has got 37 number of 60's.

and to make it perfectly divisible by 60, we have to
add (60-37=23) more to 2497

by which the number becomes 2497+23=2520

and 2520 is divisible by 60, then it is defiantly divisible by 5,6,4,3.

i hope now its easy to understand.
(1)

Gannu said:   1 decade ago
@Prashanthy K.

Like 2497/60 does give 37 as remainder so that doesn't mean that it contains 37 60's because 37x60 \= 2497.

It is remainder, not quotient.

Can anyone explain why 60-37.

Parades said:   1 decade ago
How did in 60?


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