Aptitude - Problems on H.C.F and L.C.M - Discussion

very simple

Look 60 is the common number divisible by 5,6,4& 3
ie LCM of 5,6,4,3

now when we divide 2497/60, we get 37
That means 2497 has got 37 number of 60's.

and to make it perfectly divisible by 60, we have to
add (60-37=23) more to 2497

by which the number becomes 2497+23=2520

and 2520 is divisible by 60, then it is defiantly divisible by 5,6,4,3.

i hope now its easy to understand.

How we get the remainder 37?

Guys whoever did not understand this, refer this;.

Any such problem comes, the first step is to find the lcm of the factors given.

Next step is to divide this LCM obtained by the dividend given in the question.

Now whatever remainder you obtain, subtract it from the dividend. The resulting number will be exactly divisible by the LCM.

Since they have asked the question what must be subtracted, hence the required answer will be the difference between your LCM and the remainder. In this case, 60 - 37 = 23.

I hope you understand reading this reply.

An easy method to find the lcm:

Suppose the numbers are 12, 24, 36.

Just consider the greatest number of these three and check whether the other two numbers are divisible by it.

Here 12 and 24 are not divisible by 36. Now take the 2nd multiple of 36 i.e. 72 and see if 72 divides 12 and 24. Here it does divide. Hence that is the lcm.

Try for other numbers and see the result.

Thank you @Veeresh.

Add 3,13,23,33 to 2497 separately.

2494 + 3 = 2500 likewise then these factors 5, 6, 4, 3 divided to the result it must be 0 i.e. 2497 + 23 = 2520 it is divided by 5, 6, 4, 3.

Please divide 2497 by 60 and the remainder is 41.6166666 not 37.

So 23 is not correct answer.

After LCM is 60.

Now we want to know which number is added to make divided 2497 with 60.

2497/60 = 41 but there is remeder is 37 and we want to fully divided so add 23 from the option.

Best of luck.

How to find lcm? How it comes 60? Please help.

How to divide it without Remainder?