Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 26)
26.
The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:
123
127
235
305
Answer: Option
Explanation:

Required number = H.C.F. of (1657 - 6) and (2037 - 5)

  = H.C.F. of 1651 and 2032 = 127.

Discussion:
38 comments Page 1 of 4.

Sureshkumar said:   1 decade ago
H.C.F example please

Ram said:   1 decade ago
Plz explain all

Sakthi said:   1 decade ago
HCF explain please.

Arun said:   1 decade ago
H.C.F of 1651 and 2032, Explain please.

Ramesh said:   1 decade ago
I need the calculation process for finding hcf.

Mini said:   1 decade ago
@Ramesh

It is better explained in the following link...check it out

http://www.ilovemaths.com/1lcmandhcf.asp

Patil bhatu said:   1 decade ago
H.C.F of 1651 and 2032, Explain please.

Umesh said:   1 decade ago
HCF explain please.

Santhosh said:   1 decade ago
HCF Explain & give me some examples please.

Deepak said:   1 decade ago
Division Method: Suppose we have to find the H.C.F. of two given numbers, divide the larger by the smaller one. Now, divide the divisor by the remainder. Repeat the process of dividing the preceding number by the remainder last obtained till zero is obtained as remainder. The last divisor is required H.C.F.

ans...

Required number = H.C.F. of (1657 - 6) and (2037 - 5)

= H.C.F. of 1651 and 2032
let devide the greater no with smaller one means
2030/1651=381
then,1651/381=127
then,381/127=0

so the
The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:127


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